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3 years ago

12

What is the y-intercept for the below inequality?

1 answer:

san4es73 [151]3 years ago

8 0

Answer:

The correct answer is C

Step-by-step explanation:

In order to find the y-intercept, you need to first solve the inequality for y.

5x - 3y ≤ 15

-3y ≤ -5x + 15

y ≥ 5/3x - 5

Now we look at the constant at the end. Since that constant is -5, we know C to be the answer.

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HELPPPPPPPPPP Add & subtract matrices ..... <br><br> PLZ GIVE THE ANSWER .. THANKSSSSS .

ale4655 [162]

Answer:

$\left[\begin{array}{cc}0&-1\\-1&0\\-1&-1\end{array}\right]$

Step-by-step explanation:

In this question we have to subtract the corresponding entries of column of matrix 1 and the matrix 2 corresponding entries

$=\left[\begin{array}{cc}-1&0\\1&-2\\1&3\end{array}\right]-\left[\begin{array}{cc}-1&1\\2&-2\\2&4\end{array}\right] \\=\left[\begin{array}{cc}-1-(-1)&0-1\\1-2&-2-(-2)\\1-2&3-4\end{array}\right]\\=\left[\begin{array}{cc}-1+1&-1\\-1&-2+2\\-1&-1\end{array}\right]\\=\left[\begin{array}{cc}0&-1\\-1&0\\-1&-1\end{array}\right]$

8 0

3 years ago

What is the radius of a sphere with a surface area of 100TCm ?

tensa zangetsu [6.8K]

The radius is 5cm

Step-by-step explanation:

The surface area of a sphere is given by:

$SA = 4\pi r^2$

Here

Given

SA = 100π cm^2

Putting the values in the formula

$100\pi = 4\pi r^2\\r^2 = \frac{100\pi}{4\pi}\\r^2 = 25$

Taking square root on both sides

$\sqrt{r^2} = \sqrt{25}\\r = 5 cm$

The radius is 5cm

Keywords: Surface area, Radius

Learn more about surface area of sphere at:

#LearnwithBrainly

7 0

3 years ago

If A, B, and C are collinear, and AB = 18, AC = 41, what is a possible measure of BC?

ikadub [295]

Step-by-step explanation:

As ANC are collinear,

AB+BC=AC

so,

18+BC = 41

BC = 41-18

BC = 23 is the answer.

8 0

4 years ago

Read 2 more answers

Chris has 5 apples and giselle has 8 blueberries what is the ratio from apples to blueberries

Elodia [21]

Answer:

5:8

Step-by-step explanation:

5A to 8 BB

= 5:8

7 0

4 years ago

Find the directional derivative of f(x,y,z)=z3−x2yf(x,y,z)=z3−x2y at the point (−5,5,2)(−5,5,2) in the direction of the vector v

olga_2 [115]

We are given

$f=z^3 -x^2y$

Firstly, we can find gradient

so, we will find partial derivatives

$f_x=0 -2xy$

$f_x=-2xy$

$f_y=0 -x^2$

$f_y=-x^2$

$f_z=3z^2$

now, we can plug point (-5,5,2)

$f_x=-2*-5*5=50$

$f_y=-(-5)^2=-25$

$f_z=3(2)^2=12$

so, gradient will be

$gradf=(50,-25,12)$

now, we are given that

it is in direction of v=⟨−3,2,−4⟩

so, we will find it's unit vector

$|v|=\sqrt{(-3)^2+(2)^2+(-4)^2}$

$|v|=\sqrt{29}$

now, we can find unit vector

$v'=(\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })$

now, we can find dot product to find direction of the vector

$dir=(gradf) \cdot (v')$

now, we can plug values

$dir=(50,-25,12) \cdot (\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })$

$dir=(-\frac{150}{\sqrt{29} } - \frac{50}{\sqrt{29} } - \frac{48}{\sqrt{29} })$

$dir=-\frac{248\sqrt{29}}{29}$ .............Answer

7 0

4 years ago

Read 2 more answers