Step-by-step explanation:
please mark me as brainlest
Answer:

Step-by-step explanation:
Given:
A car starts with a dull tank of gas
1/7 of the gas has been used around the city.
With the rest of the gas in the car, the car can travel to and from Ottawa three times.
Question asked:
What fractions of a tank of gas does each complete trip to Ottawa use?
Solution:
Fuel used around the city = 
Remaining fuel after driving around the city = 1 -
= 
According to question:
As from the rest of the gas in the car that is
, the car can complete 3 trip to Ottawa which means,
By unitary method:
The car can complete 3 trip by using =
tank of gas.
The car can complete 1 trip by using = 
=
= 
=
tank of gas
Thus,
tank of gas used for each complete trip to Ottawa.
Answer: d = 0
Step-by-step explanation:
5d - 4 = 4 - d
+d +d
____________
6d - 4 = 4
-4 -4
__________
6d = 0
__ __
6 6
d = 0
Answer:
a) z* = -1.97
b) z* = -2.33
c) z* = -1.65
d) z* = 2.04
e) z* = 2.33
f) z* = -1.25.
Step-by-step explanation:
Z-score:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
a. P(z < z*) = 0.0244
We have to look at the ztable, and find z which has a pvalue of 0.0244. So it is z* = -1.97
b. P(z < z*) = 0.0098
We have to look at the ztable, and find z which has a pvalue of 0.0098. So it is z* = -2.33
c. P(z < z*) = 0.0496
We have to look at the ztable, and find z which has a pvalue of 0.0496. So it is z* = -1.65
d. P(z > z*) = 0.0204
We have to look at the ztable, and find z which has a pvalue of 1 - 0.0204 = 0.9796. So z* = 2.04
e. P(z > z*) = 0.0098
We have to look at the ztable, and find z which has a pvalue of 1 - 0.0098 = 0.9902. So z* = 2.33
(f) P(z > z* or z < -z*) = 0.201
This is z which has a pvalue of 0.201/2 = 0.1055. So it is z* = -1.25.
Answer:
-6 negative six
Step-by-step explanation:
3- 2 - 1 - 4 + 2 - 4= -6