Answer:
D
Step-by-step explanation:
(2x + 2) - 
(3x - 1) = 15
multiply through by 4 ( the LCM of 2 and 4 ) to clear the fractions
2(2x + 2) - (3x - 1) = 60 ← distribute parenthesis and simplify left side
4x + 4 - 3x + 1 = 60
x + 5 = 60 ( subtract 5 from both sides )
x = 55
it will be c
as
negative with negative erased together
Answer:
f(x)=(x-1)^2+5 with domain x>1 and range y>5 has inverse g(x)=sqrt(x-5)+1 with domain x>5 and range y>1.
Step-by-step explanation:
The function is a parabola when graphed. It is in vertex form f(x)=a(x-h)^2+k where (h,k) is vertex and a tells us if it's reflected or not or if it's stretched. The thing we need to notice is the vertex because if we cut the graph with a vertical line here the curve will be one to one. So the vertex is (1,5). Let's restrict the domain so x >1.
* if x>1, then x-1>0.
* Also since the parabola opens up, then y>5.
So let's solve y=(x-1)^2+5 for x.
Subtract 5 on both sides:
y-5=(x-1)^2
Take square root of both sides:
Plus/minus sqrt(y-5)=x-1
We want x-1>0:
Sqrt(y-5)=x-1
Add 1 on both sides:
Sqrt(y-5)+1=x
Swap x and y:
Sqrt(x-5)+1=y
x>5
y>1
Is your question true or false?
2abc - 3ab = -30? if a =2, b = -3 and c= 4
plug in
2(2)(-3)(4) - 3(2)(-3) = -30
Simplify
-48 + 18 = -30
-30 = -30
Both sides are equal so
It's true.
Answer:
-x^2 +9x -2
Step-by-step explanation:
f(x) = – x^2 + 6x - 1 and g(x) = 3x
- 1,
(f + g)(x) = f(x) + g(x)
= – x^2 + 6x - 1 + 3x
- 1
Combine like terms
= -x^2 +9x -2
