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3 years ago

If the area of a circle is

Mathematics

1 answer:

ozzi3 years ago

5 0

Answer:

Since area =7.7

$area = \frac{22}{7} {(r)}^{2} \\ {(r)}^{2} = 2.45 \\ r = 1.57$

Then the circumference is

$c = 2pi\times r \\ = 2 \times 3.14 \times 1.57 \\ = 9.859$

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PLZ HELP!! <br><br> describe a real world situation when opposite qualities combine to make zero.

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3 years ago

what is the measure of the base angle,x, of the isosceles triangle shown below? round your answer to the nearest tenth of a degr

MAVERICK [17]

Answer:

x ≈ 49.7°

Step-by-step explanation:

Since, the given triangle is an isosceles triangle,

Two sides having measure 17 units are equal.

Opposite angles of these equal sides will be equal.

Measure of the third angle = 180° - (x + x)°

By sine rule,

$\frac{\text{sinx}}{17}=\frac{\text{sin}(180-2x)}{22}$

$\frac{\text{sinx}}{17}=\frac{\text{sin}(2x)}{22}$ [Since, sin(180 - θ) = sinθ]

$\frac{\text{sinx}}{17}=\frac{2(\text{sin}x)(\text{cos}x)}{22}$

$\frac{\text{sinx}}{17}=\frac{(\text{sin}x)(\text{cos}x)}{11}$

$\frac{1}{17}=\frac{(\text{cos}x)}{11}$

cos(x) = $\frac{11}{17}$

x = 49.68°

x ≈ 49.7°

4 0

3 years ago

Please help! It's due tomorrow! 15 points!:

ludmilkaskok [199]

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3 years ago

Read 2 more answers

If y=3x+5 and z=x^2+2x-5, what is yz?

Hitman42 [59]

<h3>Answer: 3x^3 + 11x^2 - 5x - 25</h3>

Work Shown:

yz = y(x^2+2x-5)

yz = y(x^2) + y(2x) + y(-5)

yz = x^2( y ) + 2x( y ) - 5( y )

yz = x^2( 3x+5 ) + 2x( 3x+5 ) - 5( 3x+5 )

yz = x^2*3x + x^2*5 + 2x*3x + 2x*5 - 5*3x - 5*5

yz = 3x^3 + 5x^2 + 6x^2 + 10x - 15x - 25

yz = 3x^3 + 11x^2 - 5x - 25

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1 year ago

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yulyashka [42]

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3 years ago