2x+4y=0
3x+y=10
So what we want to do is get y onto one side by itself using whatever equation you like.
So I'm taking 2x+4y=0 and subtracting 4y from both sides
So we end up with
2x=4y
Divide both sides by four
2/4x is 1/2 x
So we get 1/2x=y
Take this and plug it into the other equation
3x+y=10
3x+1/2x=10
Add your like terms
3 1/2x=10
Putting 3 1/2 as a mixed number we get 7/2
So..
7/2x=10
Multiply by the opposite of 7/2 on both sides
Which is 2/7 this will cancel out the left side.
So we end up with
X= 10•2/7
X=20/7
Which is 2 and 6/7 as a mixed number.
Answer:
y > 1/2x - 1
First, draw the dashed line y = 1/2x - 1 (slope intercept ; y = mx + b).
Start at -1 on the y-axis, and continue going 2 units to the right, and 1 unit up for the right side of the graph.
Then starting at -1 on the y-axis, continue going 2 units to the left, and 1 unit down for the left side of the graph.
Explanation:
Convert standard form (Ax + By = C) by isolating y from the rest of the equation.
Ax + By = C → y = -Ax/B + C/B → y = mx + b.
Given a standard form equation in inequality form,
x - 2y < 2.
Set it to slope-intercept as an inequality to find the slope and y-intercept.
When negating (making opposite) a variable, you flip the inequality.
x - 2y < 2 → x - 2y - x < 2 - x → -2y < -x + 2 → 2y > x - 2 → <u>y > 1/2x - 1</u><u>.</u>
We can use the SSS congruence theorem to prove that the two triangles in the attached figure are congruent. The SSS or side-side-side theorem states that each side in the first triangle must have the same measurement or must be congruent on each of the opposite side of another triangle. In this problem, for the first triangle, we have sides AC, CM, AM while in the second triangle we have sides BC, CM, and BM. By SSS congruent theorem, we have the congruent side as below:
AC = BC
CM = CM
AM = BM
The answer is SSS theorem.
Answer:
The distance between the two points is 13 units.
Step-by-step explanation:
take the test
#1 4/5x + 2/3x = 1 -4/15
22/15x = 11/15
x = 1/2
and can u explain what u mean by #2 and #3??
