The speed of the ball is
ds/dt = 32t
At t =1/2 s
ds/dt = 16 ft/s
The distance from the ground
50 - 16(1/2)^2 = 46 ft
The triangles formed are similar
50/46 = (30 + x)/x
x = 345 ft
50 / (50 - s) = (30 + x)/x
Taking the derivative and substituing
ds/dt = 16
and
Solve for dx/dt
3(2(5)+4)-5
3(10+4)-5
30+12-5
42-5
37
Let the both the parts be 'x' and 'y'
x>y
We know that 4x = 5y
so x = 5y/4
x + y = 54
Replacing x we get
(5y/4) + y = 54
(5y +4y)/4 = 54
9y = 216
y = 24
Replacing y in ' x+y = 54'
we get x = 30
Hence the larger part is 30 whereas the smaller part is 24
Answer:
B. 14 = 125p
Step-by-step explanation:
Answer:
there are 2 solutions in total
Step-by-step explanation:
x^2-4=0
x^2=4
x= ±2<em>i</em>