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3 years ago

If the quadratic formula is used to solve 2x 2 - 3x - 1 = 0, what are the solutions?

2 answers:

8 0

Hello :
the discriminat of each quadratic equation : ax²+bx+c=0 ....(a ≠ 0) is :
Δ = b² -4ac
1 ) Δ > 0 the equation has two reals solutions : x = (-b±√Δ)/2a
2 ) Δ = 0 : one solution : x = -b/2a
3 ) Δ < 0 : no reals solutions
in this exercice : 2x ² - 3x - 1 = 0....a =2 b =-3 c =-1
calculate : Δ ......................................

PSYCHO15rus [73]3 years ago

8 0

The correct answer is Option (C):

3 +/- $\sqrt{17}$ / 4

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Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: $f(x) = A cos (kx)$

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