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Y_Kistochka [10]
3 years ago
7

Which relation is a function?

Mathematics
2 answers:
OLga [1]3 years ago
7 0
B is the answer you got it
Doss [256]3 years ago
5 0

Answer:

B

Step-by-step explanation:

All functions have y with a power of 1.

option B. is the only one where y has a power of 1.

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Sales tax she paid I . L . N 2-
goldenfox [79]
Rounded it equals $30. It was really like $29.83 :)
4 0
3 years ago
Mike jogged a total distance of 5 1/3 miles during the months of October and November. If Mike only jogger 1/6 mile every day, W
Bumek [7]

Answer:

D

Step-by-step explanation:

If he jogged x miles every day, and he jogged a total distance of y miles, then he runs for y/x days. This is an extension of the d=rt or distance equals rate times time.

We plug in for y and x to get that he runs for 5~1/3~~/~~1/6.

So, the answer is \boxed{D} and we're done!

7 0
2 years ago
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Whats 3x3+4 use pemdas ?
Romashka [77]

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13

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8 0
2 years ago
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A beach ball a radius 15 centimeters what is the volume of the beach ball?
sladkih [1.3K]

Answer:

volume = 4/3 (pi x r^3)

Volume = 4/3 (pi x 15^3)

Volume = 4/3 (3.14 x 3375)

Volume = 14130 cubic cm

Step-by-step explanation:

4 0
3 years ago
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The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).
BabaBlast [244]

Step-by-step explanation:

the introduction of a fraction tells us that we are dealing with multiplications, and therefore a geometric sequence (where every new term is created by multiplying the previous term by a constant factor, the ratio r).

I think your teacher made a mistake, or you made one when typing the question in here.

there is no factor r that creates

15×r = 9

and

9×r = 5/27

it would mean that

15 × r² = 5/27

r² = 5/27 / 15 = 5/27 × 1/15 = 5/405 = 1/81

r = 1/9

but 15 × 1/9 = 5 × 1/3 = 5/3 is NOT 9

and 9 × 1/9 = 9/9 = 1 is NOT 5/27

so, this can't be right.

on the other hand

15 × r = 9

r = 9/15 = 3/5

and then

9 × 3/5 = 27/5

so, either the sequence should have been

15, 5/3, 5/27

or (and I suspect this to be true)

15, 9, 27/5

under that assumption we have

s1 = 15

r = 3/5

sn = sn-1 × r = s1 × r^(n-1) = 15 × (3/5)^(n-1)

s10 = 15 × (3/5)⁹ = 15 × 19683/1953125 =

= 3 × 19683/390625 = 59049/390625 =

= 0.15116544 ≈ 0.151

6 0
2 years ago
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