6.3 x 10^14
es {10}^{14?} " alt="6.3 \times {10}^{14?} " align="absmiddle" class="latex-formula">
1 answer:
I'm assuming you're looking to find the expanded form of the number?
This number is in scientific notation. The easiest way to convert it to a normal number is to move the decimal place 14 to the right. I've attached a picture showing how to do this. You should get 630,000,000,000,000
There's a faster way to do this - notice that you need to move the decimal 14 to the right, and there's one number already after the decimal place. Therefore, 13 places will be filled with zeros. So, just write out 63 and add 13 zeros.
For more general help on scientific notation, check out these videos: https://www.khanacademy.org/math/pre-algebra/pre-algebra-exponents-radicals/pre-algebra-scientific-notation/v/scientific-notation-old
Hope that helps! Feel free to message me or leave a comment if I can clarify anything :)
You might be interested in
Answer:
The probability that an employee receives a code with all 5 numbers the same is .
Step-by-step explanation:
Consider the provided information.
The numbers which we can use in code is: 0,1,2,3,4,5,6,7,8,9
That means there are 10 numbers which we can use.
The total ways of selecting a 5 digit number with all 5 numbers the same = 10.
The total ways of selecting a 5 digit number is: 10×10×10×10×10=
The required probability is:
Hence, the probability that an employee receives a code with all 5 numbers the same is .
i) We have to find the determinant of A.
We can do this as:
ii) We have to find if the matrix A is singular.
Singular matrix have determinant equal to 0.
This is not the case for A, as its determinant is -12. Then, A is not a singular matrix.
iii) We have to find the values of x and y so that AB = C.
We have to write the matrix multiplication and we will obtain a system of linear equations:
We can now solve the system of equations by adding 3 times the second equation to the first equation:
We can now use the second equation to find the value of y:
The values are x = -2 and y = 1/2.
iv) When we want to multiply two matrices, the required condition is that the number of columns of the matrix on the left is equal the number of rows of the matrix on the right.
In the case of A(2x2) and B(2x1), when we do A*B this condition is satisfied.
But when we try to multiply BA, the number of columns of B is not equal to the number of rows of A, so the matrix mulitplication is not possible.
Answer:
i) det(A) = -12
ii) A is not singular because singular matrices have determinant equal to zero.
iii) x = -2 and y = 1/2.
iv) Is not possible because the number of columns of the first matrix has to be equal to the number of rows of the second matrix.
