Can you take a pic of the question because the link is not working
1) slope=3 and y-int.=-5
2) slope=2 and y-int.=-6
3) slope=-6 and y-int.=1/2
4) slope=-7 and y-int.=5/2
5) slope=1/2 and y-int.=7
6) slope=3/4 and y-int.=8
7) slope=-2/3 and y-int.=-1/3
8) slope=-1/8 and y-int.=-3/8
9) slope=2/3 and y-int.=5
10) slope=-2/7 and y-int.=-1
11) slope=-3 and y-int.=6
12) slope=4 and y-int.=7
Hope this helps!
Check the picture below. So the parabola looks more or less like so.
let's recall that the vertex is half-way between the focus point and the directrix, at "p" units away from both.
Let's notice that the focus point is below the directrix, that means the parabola is vertical, namely the squared variable is the "x", and it also means that it's opening downwards as you see in the picture, namely that "p" is negative, in this case "p" is 1 unit, and thus is -1.
![\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ \stackrel{\textit{we'll use this one}}{4p(y- k)=(x- h)^2} \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-2\\ k=5\\ p=-1 \end{cases}\implies 4(-1)(y-5)=[x-(-2)]^2\implies -4(y-5)=(x+2)^2 \\\\\\ y-5=-\cfrac{1}{4}(x+2)^2\implies y=-\cfrac{1}{4}(x+2)^2+5](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bparabola%20vertex%20form%20with%20focus%20point%20distance%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%204p%28x-%20h%29%3D%28y-%20k%29%5E2%20%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bwe%27ll%20use%20this%20one%7D%7D%7B4p%28y-%20k%29%3D%28x-%20h%29%5E2%7D%20%5Cend%7Barray%7D%20%5Cqquad%20%5Cbegin%7Barray%7D%7Bllll%7D%20vertex%5C%20%28%20h%2C%20k%29%5C%5C%5C%5C%20p%3D%5Ctextit%7Bdistance%20from%20vertex%20to%20%7D%5C%5C%20%5Cqquad%20%5Ctextit%7B%20focus%20or%20directrix%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%20h%3D-2%5C%5C%20k%3D5%5C%5C%20p%3D-1%20%5Cend%7Bcases%7D%5Cimplies%204%28-1%29%28y-5%29%3D%5Bx-%28-2%29%5D%5E2%5Cimplies%20-4%28y-5%29%3D%28x%2B2%29%5E2%20%5C%5C%5C%5C%5C%5C%20y-5%3D-%5Ccfrac%7B1%7D%7B4%7D%28x%2B2%29%5E2%5Cimplies%20y%3D-%5Ccfrac%7B1%7D%7B4%7D%28x%2B2%29%5E2%2B5)
Answer:
T = 60 degrees
Step-by-step explanation:
The dotted line is the height so it is a right angle
We are able to use trig functions since this is a right triangle
cos T = adj side / hyp
cos T = a/b
cos T = 8 sqrt(2) / 16 sqrt(2)
cos T = 1/2
Taking the inverse of each side
cos^-1 ( cosT) = cos^-1 ( 1/2)
T = 60 degrees
For the first die, 5 out of 6 are not 1.
That is 5/6.
For the second die, 3 out of 4 are not 1.
That is 3/4.
Multiply 5/6 by 3/4 to get the probability.
5/6 x 3/4 = 20/72
Simplify once to get 10/36.
Do it again to get 5/18.
In decimal form it is 0.2777 and in percent form it is 27.77%.
Hope this helps!
