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3 years ago

6

a meal cost $15. we gave the waiter $18 and told him that the difference was his tip. what percent of the cost of the meal was t

he tip we gave?

2 answers:

Stella [2.4K]3 years ago

6 0

18 - 15 = 3
3/15 = n/100
15n = 300
n = 20

olga2289 [7]3 years ago

6 0

83 percent.
You gave them 18 dollars. As a percentage, your answer is 83%

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Charles owes $2,500 on a credit card. The card charges 12% interest compounded continuously. Write a formula that describes how

ella [17]

Answer:

see below

Step-by-step explanation:

The formula for the amount resulting from P earning interest at rate r continuously compounded is ...

A = Pe^(rt)

for P=2500 and r=0.12, this becomes ...

A = 2500e^(0.12t)

4 0

3 years ago

If you get this right I will mark you as a brainliest

svp [43]

The answer would be D.

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3 years ago

The table shows how many books the students in Bergdalsskolan list during the summer. There were 48 students who list 4 books. a

Juliette [100K]

Step 1:

First, find the total number of students.

Let the total number of students = m

Step 2:

Find the total number of students using the percentage of 4 books.

48 students listed 4 books with a percentage of 16%

$\begin{gathered} 48\text{ = 16\% of m} \\ 48\text{ = }\frac{16}{100}\text{ }\times\text{ m} \\ 48\text{ = }\frac{16m}{100} \\ \text{Cross multiply} \\ 16m\text{ = 48 }\times\text{ 100} \\ 16m\text{ = 4800} \\ \text{m = }\frac{4800}{16} \\ \text{m = 300} \end{gathered}$

Hence, there are 300 students.

a)

$\begin{gathered} \text{Number of students that had 1 book = 24\% of 300} \\ =\text{ }\frac{24}{100}\text{ }\times\text{ 300} \\ =\text{ }\frac{7200}{100} \\ =\text{ 72 students} \end{gathered}$

72 students had 1 book.

b) What percentage more read 2 books than 4 books?

percentage that read 2 books = 36%

percentage that read 4 books = 16%

36 - 16 = 20%

There are 20% students that read 2 books than 4 books.

8 0

2 years ago

Help pleaseeeeeeeeeeeeeeee

kupik [55]

Answer:C

Step-by-step explanation:

your answer is 390

First area of the rectangle which formula is bxh base time height.

that gives you 300 since 15x20=300

The for the triangle Formula is Basexheight deivded by 2

so 15x12 devided by 2 =90

300+90=390

Hope this helps you. :)

8 0

3 years ago

Evaluate the following integral using trigonometric substitution.

wariber [46]

Answer:

Step-by-step explanation:

1. Given the integral function $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ , using trigonometric substitution, the substitution that will be most helpful in this case is substituting x as $asin \theta$ i.e $x = a sin\theta$ .

All integrals in the form $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ are always evaluated using the substitute given where 'a' is any constant.

From the given integral, $\int\limits {7\sqrt{49-x^{2} } } \, dx = \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx$ where a = 7 in this case.

The substitute will therefore be $x = 7 sin\theta$

2.) Given $x = 7 sin\theta$

$\frac{dx}{d \theta} = 7cos \theta$

cross multiplying

$dx = 7cos\theta d\theta$

3.) Rewriting the given integral using the substiution will result into;

$\int\limits {7\sqrt{49-x^{2} } } \, dx \\= \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -(7sin\theta)^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -49sin^{2}\theta } } \, dx\\= \int\limits {7\sqrt{49(1-sin^{2}\theta)} } } \, dx\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, dx\\since\ dx = 7cos\theta d\theta\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, 7cos\theta d\theta\\= \int\limits {7\{7(cos\theta)} }}} \, 7cos\theta d\theta\\$

$= \int\limits343 cos^{2} \theta \, d\theta$

8 0

4 years ago