So, bike=b and accessories=a.
b+a=320
Since the bike is worth 7 times more than the accessories, the b would turn into 7a (because 7 times the cost of accessories is the cost of the bike).
The equation would now turn into 7a+a=320.
Solve for a.
7a+a=320
8a=320
a=40
Now that you know the cost of the accessories, you multiply that 40
by 7 to get the cost of the bike.
40(7)
280
The cost of the bike is $280.
The cost of the accessories are/is $40.
Start with 180.
<span>Is 180 divisible by 2? Yes, so write "2" as one of the prime factors, and then work with the quotient, 90. </span>
<span>Is 90 divisible by 2? Yes, so write "2" (again) as another prime factor, then work with the quotient, 45. </span>
<span>Is 45 divisible by 2? No, so try a bigger divisor. </span>
<span>Is 45 divisible by 3? Yes, so write "3" as a prime factor, then work with the quotient, 15 </span>
<span>Is 15 divisible by 3? [Note: no need to revert to "2", because we've already divided out all the 2's] Yes, so write "3" (again) as a prime factor, then work with the quotient, 5. </span>
<span>Is 5 divisible by 3? No, so try a bigger divisor. </span>
Is 5 divisible by 4? No, so try a bigger divisor (actually, we know it can't be divisible by 4 becase it's not divisible by 2)
<span>Is 5 divisible by 5? Yes, so write "5" as a prime factor, then work with the quotient, 1 </span>
<span>Once you end up with a quotient of "1" you're done. </span>
<span>In this case, you should have written down, "2 * 2 * 3 * 3 * 5"</span>
Answer:
A . (2,4)
Step-by-step explanation:
Let's solve for x.
x+2y≤4
Step 1: Add -2y to both sides.
x+2y+−2y≤4+−2y
x≤−2y+4
Answer:
x≤−<u>2</u>y+<u>4</u>
C. 4
14 + 13 - (23)
27 - 23
4
Answer:
1) b, c, d
2) d
3) a, c, d
Step-by-step explanation:
Just find the number that can divide by the whole. Say the question was
A pet shop have 20 pets. The same amount of pets are in each room. How many rroms could there be?
If there were 4 rooms, 5 pets would be in each. 20÷4=5. 4 goes into 20 so 4 could be an answer.
If there were 3 rooms, 6 rooms would have 3 pets and 2 would be left over. So it wouldn't work. You just need to find the number that goes into the whole with no remainder.
