let's notice the tickmarks on the left and right sides, meaning those two sides are twins, and therefore equal, so the perimeter is simply 2.5+2.5+3.5+2.5 = 11 ft.
the trapezoid has an altitude/height of 2 ft, thus
![\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\[-0.5em] \hrulefill\\ a=2.5\\ b=3.5\\ h=2 \end{cases}\implies A=\cfrac{2(2.5+3.5)}{2}\implies A=6](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20a%2Cb%3D%5Cstackrel%7Bbases%7D%7Bparallel~sides%7D%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D2.5%5C%5C%20b%3D3.5%5C%5C%20h%3D2%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B2%282.5%2B3.5%29%7D%7B2%7D%5Cimplies%20A%3D6)
Answer:
its in order OK
2/15 2/5 1/30 9/40 1/6 3/5 7/20 4/25 1/4
Answer: Remember that the tens place is two moves to the left of the decimal point (if it exists). To round to the nearest ten (nearest 10), we use the whole numbers place to determine whether the tens place rounds up or stays the same.
Solution steps:
Step 1: Locate and underline the tens place () and look to digit to the right (6):
36
Step 2: In this case, the digit to the right 6 is 5 or above. So, we add 1 to the tens place (). The digit(s) after the (6) are dropped. Thus, we get 40 as answer.
In short: 36 rounded to the nearest tens is 40.
Step-by-step explanation:
If I’m right I think the answer is 1,759.32
