Question

an isosceles triangle has legs that are 10 inches long and a base that is 4 inches long what is the measure of one of the base angle of this triangle to the nearest degree

Answer 1

Answer:

The angle between the base an a leg is 78.463° or 1.369 radians.

Step-by-step explanation:

We have an isosceles triangule with 2 sides of 10 in. and the other side of 4 in. We have to calculate one of the angles between the base (4 in.) and a leg (10 in.)

If we divide the triangle in half, we came with 2 rectangule triangles. We can use trigonometry relationships to calculate the angle.

We can relate the leg and the base as:

$L\cdot cos(\alpha)=B/2\\\\cos(\alpha)=B/(2L)=4/(2*10)=0.2\\\\\alpha=arc\, cos(0.2)=1.369\,rad=78.463^{\circ}$