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allochka39001 [22]
3 years ago
7

For what values of x and y are the triangles congruent?

Mathematics
2 answers:
KatRina [158]3 years ago
7 0
For y
since both triangles are congruent,
6y-8=2y+8
4y=16
y=4
For x
5x-5y=2y+7
since y is 4, substitute y to 4
so,
5x-5(4)=2(4)+7
5x-20=15
5x=35
x=7
olya-2409 [2.1K]3 years ago
3 0

Yeah, what he said...x=7 :)

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Answer:

  y < -1/4x -1

Step-by-step explanation:

The boundary line appears to go through the points (-4, 0) and (0, -1). This tells you it has a "rise" of -1 for a "run" of 4. The slope is ...

  m = rise/run = -1/4

The y-intercept (b) is the point where the y-axis is crossed. The slope-intercept equation of the boundary line is ...

  y = mx + b

  y = -1/4x -1

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The boundary line is dashed, so is not included in the solution set. The shading is below the line, so all y-values less than (but not equal to) the boundary line are in the solution set:

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The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9

<h3>How to determine the quadratic equation?</h3>

From the question, the given parameters are:

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The quadratic equation is then calculated as

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Substitute the known values in the above equation

So, we have the following equation

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This gives

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f(x) = x^2 + \frac{2}{3}x - \frac{1}{9}

So, we have

f(x) = x²+ 2/3x - 1/9

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