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posledela
4 years ago
13

An expression is shown below:

Mathematics
2 answers:
wlad13 [49]4 years ago
5 0

Answer:

\sqrt{18}+\sqrt{2}\text{ is irrational and equal to }4\sqrt2

Step-by-step explanation:

Given the expression

\sqrt{18}+\sqrt{2}

we have to choose the true expression

\sqrt{18}+\sqrt{2}=\sqrt{9\times 2}+\sqrt{2}

=3\sqrt2+\sqrt2

=4\sqrt2

\text{As }\sqrt2\text{ is irrational implies that }\sqrt{18}+\sqrt{2}\text{ is irrational and equal to }4\sqrt2

Last option is correct

chubhunter [2.5K]4 years ago
3 0
It is irrational and is = to 4√2
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Use the multiplication rule to find the probability that the first four guesses are wrong and the fifth is correct. That is, fin
BabaBlast [244]

Complete question is;

Multiple-choice questions each have 5 possible answers, one of which is correct. Assume that you guess the answers to 5 such questions.

Use the multiplication rule to find the probability that the first four guesses are wrong and the fifth is correct. That is, find P(WWWWC), where C denotes a correct answer and W denotes a wrong answer.

P(WWWWC) =

Answer:

P(WWWWC) = 0.0819

Step-by-step explanation:

We are told that each question has 5 possible answers and only 1 is correct. Thus, the probability of getting the right answer in any question is =

(number of correct choices)/(total number of choices) = 1/5

Meanwhile,since only 1 of the possible answers is correct, then there will be 4 incorrect answers. Thus, the probability of choosing the wrong answer would be;

(number of incorrect choices)/(total number of choices) = 4/5

Now, we want to find the probability of getting the 1st 4 guesses wrong and the 5th one correct. To do this we will simply multiply the probabilities of each individual event by each other.

Thus;

P(WWWWC) = (4/5) × (4/5) × (4/5) × (4/5) × (1/5) = 256/3125 ≈ 0.0819

P(WWWWC) = 0.0819

4 0
3 years ago
What is the exponent in the power of 10?
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3 years ago
1. On which road would there be a larger standard deviation in speed: a backroad or an interstate? Justify your answer
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Answer:

Your answers may vary slightly. 5.2 Normal Distributions: Finding Probabilities If you are given that a random variable Xhas a normal distribution, nding probabilities corresponds to nding the area between the standard normal curve and the x-axis, using the table of z-scores. The mean (expected value) and standard deviation ˙should be given

Step-by-step explanation:

7 0
4 years ago
Test scores are normally distributed with a mean of 500. Convert the given score to a z-score, using the given standard deviatio
Bond [772]

Answer:

The percentage of students who scored below 620 is 93.32%.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 500, \sigma = 80

Percentage of students who scored below 620:

This is the pvalue of Z when X = 620. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{620 - 500}{80}

Z = 1.5

Z = 1.5 has a pvalue of 0.9332

The percentage of students who scored below 620 is 93.32%.

3 0
3 years ago
Read 2 more answers
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