Answer:
x = 600 m
y = 1200 m
Amax = 720000 m²
Step-by-step explanation:
Let call x the smaller side of the rectangular plot and y the largest ( we assume we have one y side bounded by a river: Then
A(p) Area of the plot x*y
A(p) = x*y
And perimeter of the plot ( to be fenced ) is:
P(p) = 2*x + y = 2400 ⇒ y = 2400 - 2*x
Area of rectangular plot as function of x:
A(x) = x * ( 2400 - 2x )
Taking derivatives on both sides of the equation
A´(x) = ( 2400 - 2x ) + (-2) *x ⇒ A´(x) = ( 2400 - 2x ) - 2x
A´(x) = 0 ⇒ 2400 - 4x = 0 ⇒ 4x = 2400
x = 600 m
And y = 2400 - 2*x
y = 2400 - 1200
y = 1200 m
And the largest enclosed area is Amax = 1200*600
Amax = 720000 m²
82.4+108.6=191 and 12052.1 divided by 191=63.1
So the answer is 63.1
Answer:
y = -2x + 27
Step-by-step explanation:
Firstly, we shall need to reform the given line equation;
y-7 = 1/2 ( x + 2)
y - 7 = x/2 + 1
y = x/2 + 1 + 8
y = x/2 + 8
Comparing this with y = mx + c
where m is the slope, then the slope of the line is 1/2
Since the line we are looking for has a slope perpendicular to this line, it means that the product of their slopes is -1
m1 * m2 = -1
1/2 * m2 = -1
m2 = -2
So we want an equation with slope -2 passing through (6,15)
we use the point slope method here;
y-y1 = m(x-x1)
y-15 = -2(x-6)
y-15 = -2x + 12
y= -2x + 12 + 15
y = -2x + 27
I would decrease 75% for example if you take 2/4 and do the problem above it becomes 1/3 therefore it is 75%
First, add up all of you numbers and then divide by 5 since there are five of them.
3+4+9+13+16=936
936/5=187.2
187.2
