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Kipish [7]
3 years ago
9

I need help with these questions pleaseee

Mathematics
1 answer:
AlladinOne [14]3 years ago
8 0
30
factored is
(x-3)(x-4)=0
roots are 3 and 4

E is answer


31. x+2=0 and 2x-1=0
C is answer
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Help would be much appreciated, thanks :)!
GenaCL600 [577]
Can you zoom in a little? I can’t teally see it too well
3 0
4 years ago
I need help plz. Show your work! 23 + 5 x 3 - 100 + 19 in PEMDAS!
DaniilM [7]

Answer:

-43

Step-by-step explanation:

Follow PEMDAS as well as the left -> right rule.

Note that: PEMDAS =

Parenthesis

Exponents (& Roots)

Multiplication

Division

Addition

Subtraction

First, solve the multiplication:

23 + (5 * 3) - 100 + 19

23 + (15) - 100 + 19

Simplify. Follow the left-> right rule:

(23 + 15) - 100 + 19

38 - 100 + 19

(38 - 100) + 19

-62 + 19 = -43

-43 is your answer.

~

6 0
3 years ago
Read 2 more answers
When evaluating (6.28x10^12)\(3.14x10^4)
anzhelika [568]

Answer:??? rest of the question I think is what will be the exponent of 10 in the quotient? answer is 8

Step-by-step explanation:

7 0
2 years ago
y = c1 cos(3x) + c2 sin(3x) is a two-parameter family of solutions of the second-order DE y'' + 9y = 0. If possible, find a solu
Misha Larkins [42]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value is  y  =  5sin3x

Step-by-step explanation:

From the question we are told that  

   y =  c_1\ cos3x + c_2 \  sin 3x

given that y(0) =  0

We have that  

     c_1\ cos3(0) + c_2 \  sin 3(0)  =  0

=>   c_1 =  0

This means that

           y  =  c_2 \  sin 3x

We also given that

          y[\frac{\pi}{6} ] =  5

So  

         c_2  sin (3 *  \frac{\pi}{6} )  =  5

=>    c_2  =  5

Hence  

     y  =  5sin3x

6 0
3 years ago
If 2^x=3^y=12^z, show 1/z=1/y+2/x​
weqwewe [10]

Answer:

2=k^1/x

3=k^1/y

12=k^1/z.......we get...

(atq)------k^1/x=k^1/y=k^1/z

(*a^m=b^m......b=a)

~1/x=1/y=1/z

1/z=1/y+1/x×2

(12=3+2×2)

1/z=1/y+2/x.....proved

6 0
3 years ago
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