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kupik [55]
3 years ago
14

A computer randomly picks a number from the group 105, 106, 107, 108, 109, 110, 111, 112, 113, 114. What is the probability the

number selected is 111 or smaller than 107? Enter your answer in the box as a decimal.
Mathematics
2 answers:
nikdorinn [45]3 years ago
8 0
I think 3/10 is the answer
makkiz [27]3 years ago
4 0

Answer:

Probability the number selected is 111 or smaller than 107 = 0.3

Step-by-step explanation:

Probability is the ratio of number of favorable outcome to the total number of outcomes.

Total number of outcomes when picking a number from the group 105, 106, 107, 108, 109, 110, 111, 112, 113, 114 = 10

Number less than 107 in the group are 105 and 106

Number of favorable outcome for the number selected is 111 or smaller than 107 = 3

Probability the number selected is 111 or smaller than 107 =\frac{3}{10} =0.3

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Kobotan [32]

AD = 2x -4 = 2times 32 -4 = 60

the answer is 60, hope I helped u!

5 0
3 years ago
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What percentage of a dollar is the value of each coin combination?
Brut [27]

Answer:

Step-by-step explanatinon:

percent is per hundred

4 dimes is  40 cents or $0.40 or 40/100 of a dollar which is40%

1 nickel and 3 pennies or 8 cents or $0.08 Or 8/100 or 8%

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5 0
4 years ago
See the ​attached file.
Masja [62]

f(x) = 4x - x^2

1)

f(4) = 4(4) - 4^2 = 16 - 16 = 0

f(-4) = 4(-4) - (-4)^2 = -16 - 16 = -32

f(4) - f(-4) = 0 - (-32) = 32

2)

f(3/2) = 4(3/2) - (3/2)^2

f(3/2) = 6 - 9/4 = 15/4

√f(3/2) = √(15/4) = √15 / 2

3)

f(x + h) = 4(x + h) - (x + h)^2

= 4x + 4h -(x^2 + 2xh + h^2)

= 4x + 4h -x^2 - 2xh - h^2

f(x - h) = 4(x - h) - (x - h)^2

= 4x - 4h -(x^2 - 2xh + h^2)

= 4x - 4h -x^2 + 2xh - h^2

So

[f(x + h) -f(x - h) ] / 2h

= [4x + 4h -x^2 - 2xh - h^2 - ( 4x - 4h -x^2 + 2xh - h^2 )] / 2h

=( 4x + 4h -x^2 - 2xh - h^2 - 4x + 4h + x^2 - 2xh + h^2 ) / 2h

= (8h - 4xh) / 2h

= 2h(4 -2x) / 2h

= 4 - 2x

Answer: [f(x + h) -f(x - h) ] / 2h = 4 - 2x

3 0
3 years ago
14 POINTS 7x - 3 = 18
Svetlanka [38]
Subtract 3 first so it would be 7x=15
then divide by 7 so x would be approximately 2.14
5 0
3 years ago
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P^2=mx/t-t^2x make x the subject
belka [17]

Answer:

x=\frac{P^2t}{(m-t^3)}

Step-by-step explanation:

P^2=\frac{mx}{t} -t^2x\\\\P^2+t^2x=\frac{mx}{t}\\\\t(P^2+t^2x)=mx\\\\P^2t+t^3x=mx\\\\P^2t=mx -t^3x\\\\P^2t=x(m-t^3)\\\\\frac{P^2t}{(m-t^3)} =\frac{x(m-t^3)}{(m-t^3)} \\\\\frac{P^2t}{(m-t^3)}=x

4 0
2 years ago
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