Get a common denominator to compare
7/8 = 28/32
27/32 < 28/32
7/8 is larger than 27/32
Answer:
B
Step-by-step explanation:
1. Find where the line crosses on the y-axis
2. Find two corresponding points on the graph and do the rise/run method, which in this problem is 4/1 or 4( 4÷1= 4)
- When the line is like this / you rise from up and run to the right(positive), but when it is like this \ you rise from down and run to left (negative)
Ps: You should have taken the picture at a different angle 'cause I can see what you looks like and see part of your room.
Hope I was helpful =)
If we let p and t be the masses of the paper and textbook, respectively, the equations that would best represent the given in this item are:
(1) 20p + 9t = 44.4
(2) (20 + 5)p + (9 + 1)t = 51
The values of p and t from the equation are 0.6 and 3.6, respectively. Thus, each paperback weighs 0.6 pounds and each textbook weighs 3.6 pounds.
Yw and pls mark me brainiest
Answer:
The sum of all exterior angles of BEGC is equal to 360° ⇒ answer F only
Step-by-step explanation:
* Lets revise some facts about the quadrilateral
- Quadrilateral is a polygon of 4 sides
- The sum of measures of the interior angles of any quadrilateral is 360°
- The sum of measures of the exterior angles of any quadrilateral is 360°
* Lets solve the problem
- DEGC is a quadrilateral
∵ m∠BEG = (19x + 3)°
∵ m∠EGC = (m∠GCB + 4x)°
∵ The sum of the measures of its interior angles is 360°
∴ m∠BEG + m∠EGC + m∠GCB + m∠CBE = 360
∴ (19x + 3) + (m∠GCB + 4x) + m∠GCB + m∠CBE = 360 ⇒ add the like terms
∴ (19x + 4x) + (m∠GCB + m∠GCB) + m∠CBE + 3 = 360 ⇒ -3 from both sides
∴ 23x + 2m∠GCB + m∠CBE = 375
∵ The sum of measures of the exterior angles of any quadrilateral is 360°
∴ The statement in answer F is only true
Her avarage speed in miles per hour is 54
How i solved this was by 135/2.5 and i got 54
I hope this helps!
