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kupik [55]
3 years ago
14

A computer randomly picks a number from the group 105, 106, 107, 108, 109, 110, 111, 112, 113, 114. What is the probability the

number selected is 111 or smaller than 107? Enter your answer in the box as a decimal.
Mathematics
2 answers:
nikdorinn [45]3 years ago
8 0
I think 3/10 is the answer
makkiz [27]3 years ago
4 0

Answer:

Probability the number selected is 111 or smaller than 107 = 0.3

Step-by-step explanation:

Probability is the ratio of number of favorable outcome to the total number of outcomes.

Total number of outcomes when picking a number from the group 105, 106, 107, 108, 109, 110, 111, 112, 113, 114 = 10

Number less than 107 in the group are 105 and 106

Number of favorable outcome for the number selected is 111 or smaller than 107 = 3

Probability the number selected is 111 or smaller than 107 =\frac{3}{10} =0.3

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Which equation represents “nine less than k is three”?
evablogger [386]

Answer:

k - 9 = 3

And k = 12

5 0
3 years ago
Read 2 more answers
Please explain this type of problem (1+2i)(1+3i)
zhuklara [117]

Answer:

-5(1-I) is the answer

Step-by-step explanation:

(1+2i)(1+3i)

1(1+3i)+2i(1+3i)

1+3i+2i+6i^2

As i^2=-1

1+5i+6(-1)

1-6+5i

-5+5i

Taking -5 as common

-5(1-i)

I hope this will help you :)

7 0
3 years ago
Abbey purchased a poster that had a height of 2 feet and a width of 0.7 foot.What is the area of Abbey's poster?
Eduardwww [97]

Answer:

1.4 feet

Step-by-step explanation:

To determine area we multiply height X width

2 X .7 = 1.4

6 0
3 years ago
The volume of a right circular cone with radius r and height h is V = pir^2h/3.
Scorpion4ik [409]

The question is incomplete. The complete question is :

The volume of a right circular cone with radius r and height h is V = pir^2h/3. a. Approximate the change in the volume of the cone when the radius changes from r = 5.9 to r = 6.8 and the height changes from h = 4.00 to h = 3.96.

b. Approximate the change in the volume of the cone when the radius changes from r = 6.47 to r = 6.45 and the height changes from h = 10.0 to h = 9.92.

a. The approximate change in volume is dV = _______. (Type an integer or decimal rounded to two decimal places as needed.)

b. The approximate change in volume is dV = ___________ (Type an integer or decimal rounded to two decimal places as needed.)

Solution :

Given :

The volume of the right circular cone with a radius r and height h is

$V=\frac{1}{3} \pi r^2 h$

$dV = d\left(\frac{1}{3} \pi r^2 h\right)$

$dV = \frac{1}{3} \pi h \times d(r^2)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

a). The radius is changed from r = 5.9 to r = 6.8 and the height is changed from h = 4 to h = 3.96

So, r = 5.9  and dr = 6.8 - 5.9 = 0.9

     h = 4  and dh = 3.96 - 4 = -0.04

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (5.9)(4)(0.9)+\frac{1}{3} \pi (5.9)^2 (-0.04)$

$dV=44.484951 - 1.458117$

$dV=43.03$

Therefore, the approximate change in volume is dV = 43.03 cubic units.

b).  The radius is changed from r = 6.47 to r = 6.45 and the height is changed from h = 10 to h = 9.92

So, r = 6.47  and dr = 6.45 - 6.47 = -0.02

     h = 10  and dh = 9.92 - 10 = -0.08

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (6.47)(10)(-0.02)+\frac{1}{3} \pi (6.47)^2 (-0.08)$

$dV=-2.710147-3.506930$

$dV= -6.22$

Hence, the approximate change in volume is dV = -6.22 cubic units

8 0
2 years ago
About how many inches are equivalent to 3 meters? Round the number(s) needed in the table to the nearest tenth to find the appro
Burka [1]

Answer:

D

Step-by-step explanation:

three meters is 118.11 inches, so if you were to round that you would get 120 inches. That means the answer is D.

3 0
3 years ago
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