4t=r
a=pir^2
sub 4t for r
a=pi(4t)^2
a=pi16t^2
a(t)=16pi(t^2)
A. a(t)=16pi(t^2)
B. sub 4 for t
a(4)=16pi4^2
a(4)=16pi16
a(4)=16*16*3.14
a(4)=803.84 square units
A. a(t)=16pi(t^2)
B. 803.84 square units
I don't know what c you are talking about because there is no picture
Answer
Step-by-step explanation:
(15x-8y)=52
180=90+52+x
x=38
System of equations:
15x-8y=52
6x+14y=38
y=-6.5+15/8x
6x+14(-6.5+15/8x)=38
6x-91+26.25x=38
32.25x=129
x=4
15(4)-8y=52
60-8y=52
-8y=-8
y=1
x=4
Answer:
54 R 53
54 53/83
Step-by-step explanation:
4535 divided by 83 equals
54 with a remainder of 53
138 is the outlier since it is more than 1.5 * IQR past the third quartile of the data set.
With this upper outlier, the mean will be significantly higher. Without it, it will lower back down, so B is your answer
