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3 years ago

Which of these expressions shows the number of ways to arrange 3 marbles from a group of 5?

Mathematics

1 answer:

Andru [333]3 years ago

6 0

Answer: could we see the expressions please?

Step-by-step explanation:

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What percent of 25 is 20

ipn [44]

80% bc 20/25 equals 4/5 and 4/5 equals x/100 and when you do that math it equals 80%

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3 years ago

Read 2 more answers

Do the ratios 30/24 and 20/16 form a proportion?

BartSMP [9]

Answer:

Yes.

Step-by-step explanation:

Reduce both fractions.

30/24 = 5/4
20/16= 5/4

6 0

3 years ago

Ple answer this question

Rus_ich [418]

Well the perimeter is 12x2 +16x2=56cm

3 0

3 years ago

Miguels book has 208 pages. Kristens book have n fewer pages then miguels book. Write an exprssion to represent the number of pa

77julia77 [94]

Answer:

208-n

Step-by-step explanation:

208 is Miguel number and in is Kristen. Miguel has a greater number of pages than Kristen so you would have to subtract n from it. Hope this helps! :P

3 0

3 years ago

A Pew Internet poll asked cell phone owners about how they used their cell phones. One question asked whether or not during the

EastWind [94]

Answer:

a) $\hat p=\frac{471}{1024}=0.460$

The standard error is given by:

$SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0156$

And the margin of error is given by:

$ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}=1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0305$

b) The 99% confidence interval would be given by (0.429;0.491)

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Data given and notation

n=1024 represent the random sample taken

X=471 represent the people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

$\hat p=\frac{471}{1024}=0.460$ estimated proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

p= population proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

Part a

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.