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Elan Coil [88]
3 years ago
9

Identify the outlier in the data set 6, 9, 3, 2, 10, 138, 13. Then, find the mean with and without the outlier. If necessary, ro

und your answers to the nearest tenth.
A.) Outlier = 6 Mean with outlier = 25.9 Mean without outlier = 40.4

B.) Outlier = 138 Mean with outlier = 25.9 Mean without outlier = 7.2

C.) Outlier = 6 Mean with outlier = 9 Mean without outlier = 7.5

D.) Outlier = 138 Mean with outlier = 7.2 Mean without outlier = 25.9
Mathematics
1 answer:
Andrews [41]3 years ago
5 0
138 is the outlier since it is more than 1.5 * IQR past the third quartile of the data set.

With this upper outlier, the mean will be significantly higher. Without it, it will lower back down, so B is your answer
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Please answer this correctly
viva [34]

Answer:

2/5

Step-by-step explanation:

Let's find the probability of each condition first.

For P(4), there is only one option: 4. This is 1 out of 5.

For P(even), this includes 4 and 6. However, we already had 4 from our last condition so we can remove this option. This is again 1 out of 5.

Adding them together, we will get 2/5.

The answer is 2/5

3 0
3 years ago
Can someone help me on question 7b ?
Marizza181 [45]
Lengths are given to 1dp so the biggest that the lengths could be is 4.65cm and 5.35cm. if you use pythagoras on these to find hypotenuse, this is the upper bound.
4 0
2 years ago
Solve the following system by elimination:<br> 4x+3y=2<br> 5x + 4y = 3
MAXImum [283]

Answer:

5x+4y=3

- 4x+3y=2

-----------------

x+y=1

5 0
2 years ago
A class planted 130 seeds. 52 seeds grew into plants. What percent of the seeds grew into plants?
Alexus [3.1K]

Answer:

40%

Step-by-step explanation:

52/130 =.4

.4 x 100=40

5 0
3 years ago
There are 4 cards in the box with the numbers 2, 5, 6, and 8. Two cards are drawn one after the other. The second card drawn is
malfutka [58]

It is given that there are 4 cards with numbers 2, 5, 6, and 8.

1) It is required to list all the numbers available when two cards are drawn one after the other and the second card is placed at the right of the first card drawn.

To do this, find the sample space of the draw which are:

25,26,28,52,56,58,62,65,68,82,85,86

Hence, the required numbers.

2) Recall that probability is the ratio:

Probability=\frac{\text{ number of favorable outcomes}}{\text{ total number of possible outcomes}}

From the numbers listed, notice that the total number of possible outcomes is 12.

Since event A is "obtained number is even", notice that the number of even numbers in the listed numbers is 9 (26,28,52,56,58,62,68,82,86).

Hence, the number of favorable outcomes is 9.

Substituting into the probability ratio gives the required probability:

P(A)=\frac{9}{12}=\frac{3}{4}

Check the number of numbers that are a multiple of 5, notice that they are 3 (25,65,85).

Hence, the required probability of event B is:

P(B)=\frac{3}{12}=\frac{1}{4}

The number of multiple of 3 in the listed numbers is 0 since there is no number that is a multiple of 3.

Hence, the required probability of event C is:

P(C)=\frac{0}{12}=0

Answers:

1) {25,26,28,52,56,58,62,65,68,82,85,86}

2) P(A) = 3/4

P(B) = 1/4

P(C)= 0

7 0
1 year ago
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