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Elan Coil [88]
3 years ago
9

Identify the outlier in the data set 6, 9, 3, 2, 10, 138, 13. Then, find the mean with and without the outlier. If necessary, ro

und your answers to the nearest tenth.
A.) Outlier = 6 Mean with outlier = 25.9 Mean without outlier = 40.4

B.) Outlier = 138 Mean with outlier = 25.9 Mean without outlier = 7.2

C.) Outlier = 6 Mean with outlier = 9 Mean without outlier = 7.5

D.) Outlier = 138 Mean with outlier = 7.2 Mean without outlier = 25.9
Mathematics
1 answer:
Andrews [41]3 years ago
5 0
138 is the outlier since it is more than 1.5 * IQR past the third quartile of the data set.

With this upper outlier, the mean will be significantly higher. Without it, it will lower back down, so B is your answer
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Answer:

See below.

Step-by-step explanation:

Part A:

For Dog walking, he earns $30 for 5 hours of work.

He earns $36 for 6 hours of work.

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$36/6 hours = $6/hour

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To earn $66, he works 66/6 = 11 hours.

5 30

6 36

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Part B:

He earns $7/hour for yard work, so multiply the number of hours by 7 to find the money he earns.

Table for yard work

Hours     Money

5             $35

6             $42

8             $56

Part C:

For 5 hours, he earns $35 for yard work and $30 as a dog walker.

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3 0
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Suppose that you are a city planner who obtains and sample of 20 randomly selected members of a mid-sized town in order to deter
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Answer:

The critical value for the 95% confidence interval is z = 1.96.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

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The critical value for the 95% confidence interval is z = 1.96.

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3 years ago
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