1.
2x + y = 20 (multiply this equation by 5 in order to get rid of y by addition of both equations)
6x - 5y = 12
2.
10x + 5y = 100
6x - 5y = 12
(add both equations to get the below equation)
16x = 112
3. Do simple math:
x = 112/16
x = 7
4. plug in the x (7) into the first equation
2x + y =20
2*7 + y = 20
14 + y = 20
y = 6
(x, y)
answer: (7,6)
Answer: a) 48
b) 43
Step-by-step explanation:
Given : The number of students Professor Date has in his Calculus class = 31
The number of students Professor Date has in his Discrete Mathematics class = 17
(a) If we assume that there are no students who take both classes, then the total number of students Professor Date Has = 31+17=48
(b) If we assume that there are five students who take both classes, then the total number of students Professor Date Has = 31+17-5=43
Answer:
ur pfp... pls get help NOWWW
Step-by-step explanation:
pls stop this madness
Answer:
CORRECTTT
Step-by-step explanation:
BRAINLIEST PLEASEEE
The fact that the coefficients are pairwise identical (except for sign) tells you that x^2 -1 is a factor (and x-5 is the other factor). Of course, you recognize x^2-1 as a special form (the difference of squares) that is factored as (x +1)(x -1).
The zeros are x = -1, +1, +5.
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A graphing calculator confirms this.