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3 years ago

Find a cubic function with the given zeros. Square root of five., - Square root of five., -7

Mathematics

2 answers:

skelet666 [1.2K]3 years ago

8 0

$f(x)=( x-\sqrt{5}) (x +\sqrt{5} )(x+7)$

Over [174]3 years ago

3 0

The answer is:
(x-√5)(x+√5)(x+7)=0

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Need help pick 3 right answers .?

deff fn [24]

Answer:

A, B, & D

Step-by-step explanation:

Because they all have equal signs

6 0

3 years ago

The 14th term of an arithmetical progression is 15 and it's 9th term is 35 find the 15th term

AURORKA [14]

Answer:

the 15th term is 11

Step-by-step explanation:

common difference is= -4

first term is 67

4 0

2 years ago

Y=1/5x+14 when b=7? how do i solve this?

a_sh-v [17]

Answer:

Step-by-step explanation:

Y = 1/5 x + 14 where b = 7

Result:

x + 70 = 5 Y

Geometric figure:

line

Alternate forms:

x = 5 Y - 70

x - 5 Y + 70 = 0

Real solution:

Y = x/5 + 14

Solution:

Y = x/5 + 14

Integer solution:

x = 5 n, Y = n + 14, n element Z

Solution for the variable x:

3 0

3 years ago

The revenue R you receive for selling pizza slices depends on the price p that you charge per slice and is modeled by R =-16p

sp2606 [1]

Answer:

$p \geq 0$

Step-by-step explanation:

Given

$R(p) = -16p^2 + 80p + 5$

Required

Determine the domain of the function

To do this, we need to solve for the vertex, p of the function

$p= \frac{-b}{2a}$

Given the the general form of a quadratic function is:

$y = ax^2 + bx + c$

By comparison, we have:

$a = -16$ $b =80$ $c = 5$

So:

$p= \frac{-b}{2a}$

$p = \frac{-80}{-16 * 5}$

$p = \frac{-80}{-80}$

$p = 1$

Substitute 1 for p in $R(p) = -16p^2 + 80p + 5$

$R(1) = -16(1)^2 + 80(1) + 5$

$R(1) = -16 + 80 + 5$

$R(1) = 69$

This implies that

$(p, R) = (1,69)$

The interpretation of this is that;

<em>For every value of p, there's a corresponding value of R.</em>

<em>However, because p indicates price and it's impossible to have a negative price, we can say that the minimum value of p is 0;</em>

Hence, the domain is

$p \geq 0$

8 0

3 years ago

PLZ HELP ASAP

nekit [7.7K]

%27
Hope this helps have a good day

8 0

2 years ago