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solmaris [256]
3 years ago
5

Laura owes $4759 on a credit card with a 20.9% interest rate compounded monthly. What is the monthly payment she should make in

order to pay off this debt in 3 years, assuming she does not charge any more purchases with the card?
Mathematics
2 answers:
Juliette [100K]3 years ago
8 0
This can be calculated using the formula:
P = L((r/n)*(1 + r/n)^(n*t))/((1 + r/n)^(n*t) - 1)
Where:
L = 4759
r = 0.209
n = 12
t = 3
So plugging in our data:P = 4759((0.209/12)*(1 + 0.209/12)^(12*3))/((1 + 0.209/12)^(12*3) - 1)
Which will give us the amount of: $179.05 is the monthly repayments.
Other info:
Total interest:$1,686.80
Total cost:$6,445.80
kotykmax [81]3 years ago
3 0
$4759:100%=$x:120.9%, 100*x=4759*120.9, x=(4759*120.9)/100, x=$5759.631  
With interest rate Laura owes $5759.31.
3yr*12mo=36mo
$5759/36mo=159.972$/mo
Laura's <span>monthly payment is $159.972 </span>
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6 0
3 years ago
The city has an average of 13 days of rainfall for April.
zhenek [66]

Using the Poisson distribution, we have that:

  • There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.
  • There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.
  • There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

The parameters are:

  • x is the number of successes
  • e = 2.71828 is the Euler number
  • \mu is the mean in the given interval.

For this problem, the mean is given as follows:

\mu = 13

The probability of having exactly 10 days of precipitation in the month of April is P(X = 10), hence:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 10) = \frac{e^{-13}13^{10}}{(10)!} = 0.0859

There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.

The probability of having less than three days of precipitation in the month of April is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-13}13^{0}}{(0)!} \ approx 0

P(X = 1) = \frac{e^{-13}13^{1}}{(1)!} = 0.00003

P(X = 2) = \frac{e^{-13}13^{2}}{(2)!} = 0.00019

Then:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0.00003 + 0.00019 = 0.00022

There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.

For more than 15 days, the probability is:

P(X > 15) = P(X = 16) + P(X = 17) + ... + P(X = 20)

Applying the formula for each of these values and adding them, we have that P(X > 15) = 0.2364, hence:

There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

6 0
2 years ago
Subtract (5x+3)-(x+2)
Gemiola [76]

Answer:

C.  4x + 1.

Step-by-step explanation:

(5x+3)-(x+2) First remove the parentheses. Remember to distribute the negative over the second one:

= 5x + 3 - x - 2   Bring like terms together:

= 5x - x + 3 - 2   Simplify like terms:

= 4x +1.

8 0
3 years ago
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