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3 years ago

What are the four weak (noncovalent) interactions that determine the conformation of a protein?

Biology

1 answer:

Novay_Z [31]3 years ago

3 0

Ionic bonds, hydrophobic interactions, hydrogen bonds, and Vander waals forces.

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Adult echinoderms display __________ symmetry; however, their larvae display ____________ symmetry.

Novosadov [1.4K]

Pentaradial and Bilateral

Hope it helps, Good luck! (:

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3 years ago

If there is a mutation in a zygote, where is it likely to be found in the fetus?. Answer. A.The mutation will occur in all the c

BartSMP [9]

"<span>The mutation will only be found in the types of cells in the fetus that could be harmed by the mutation and not in any others" is the correct choice among the choices given. The correct option among all the options that are given in the question is the second option or option "B". I hope it helps you.</span>

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3 years ago

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Many though not all mollusks have a shell. what secretes the shell

sashaice [31]

Mantle

In mollusks with shells, the outer cells of the mantle secrete calcium carbonate and conchiolin to form the shell. The mantle is the body wall of a mollusk. It resides below the shell where it covers the body of the animal.

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3 years ago

Most fungi is spread throughout the world by

lana [24]

Most fungi is spread throughout the world by
A. Animals ??

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3 years ago

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Cystic fibrosis is an autosomal recessive disorder. In one population, the frequency of affected individuals (A 2 A 2) is 0.0004

Simora [160]

Hardy Weinberg Equilibrium

Explanation:

Hardy Weinberg Equilibrium formula for allelic frequency is: $p+q=1$

Hardy Weinberg Equilibrium formula for genotypic frequency is: $p^2+q^2+2pq=1$

Here, $p$ =frequency of dominant allele

$q$ =frequency of recessive allele

$p^2$ =frequency of dominant genotype

$q^2$ =frequency of recessive genotype

$2pq$ =frequency of heterozygous genotype

frequency of affected individuals=0.0004(given)

here,affected individuals means the one's having Cystic Fibrosis and since it is recessive disease so we can write frequency of recessive genotype as: $q^2$ =0.0004

If $q^2$ =0.0004 $q$ will be 0.02;frequency of recessive allele will be 0.02

Using the formula $p+q=1$

$p+0.02=1\\p=1-0.02=0.98$

hence,frequency of dominant allele will be 0.98

Frequency of dominant genotype will be $p^2=(0.98)^2=0.9604$
Frequency of heterozygous genotype will be $2pq=2*0.98*0.02=0.0392$

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3 years ago