Answer:
X=0.194
T=-33.6C
Explanation:
Hello!
To solve this problem use the following steps!
1. We will call the expansion valve inlet 1 and exit 2
2.Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)
through prior knowledge of two other properties such as pressure and temperature.
3. Find the enthalpy of state 1 using pressure and temperature using thermodynamic tables
h1=Enthalpy(Ammonia;T=24C;P=1000kPa)=312.9KJ/kg
4. An expansion valve is a device which does not have heat or work exchange which means that the enthalpy of state one is equal to that of state 2, so using thermodynamic tables uses the pressure of state 2 and enthalpy of state 1 to find quality and temperature
x2=Quality(Ammonia;P=100kPa;h=h1=312.9KJ/kg)
=0.194
T2=Temperature(Ammonia;P=100kPa;h=h1=312.9KJ/kg)=-33.6C
Explanation:
Below is an attachment containing the solution.
Answer:
This question is comprising many parts (a to r). That is impossible to answer in one sheet. Following are attached images having answers to most of the parts.
I hope it will help you a lot.
Explanation:
Answer:
Net discharge per hour will be 3.5325
Explanation:
We have given internal diameter d = 25 mm
Time = 1 hour = 3600 sec
So radius
We know that area is given by
We know that discharge is given by , here A is area and V is velocity
So
So net discharge in 1 hour =
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