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rodikova [14]
4 years ago
9

The cost of fixing a fault for a software product identified during the implementation phase is approximated at $32,000 USD. How

much would the same fault cost had it been identified and corrected during the analysis phase (approximate $ amount)
Engineering
1 answer:
nydimaria [60]4 years ago
4 0

Answer:

Cost of fixing the software = $ 32,000 USD

Recalling the formula for calculating post design stage = Cost x 3

= 32000 x 3 = 96,000

Now the cost would be:  

Cost = Post Delivery Cost x (Relative Design Cost/Relative Post Delivery Cost)

= 96000 x (32000/96000)

= 96000 x 0.3333

= $36,000 USD

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Sketch T-s and p-v diagrams for the Diesel cycle.
labwork [276]

Answer:

Diesel cycle:

    All diesel engine works on diesel cycle.It have four processes .These four processes are as follows

1-2.Reversible adiabatic compression

2-3.Heat addition at constant pressure

3-4.Reversible adiabatic expansion

4-1.Heat addition at constant volume

When air inters in the piston cylinder after that it compresses and gets heated due to compression after that heat addition take place at constant pressure after that power is produces when piston moves to bottom dead center.

From the diagram of P-v And T-s we can understand so easily.

3 0
4 years ago
(3) Calculate the heat flux through a sheet of brass 7.5 mm (0.30 in.) thick if the temperatures at the two faces are 150°Cand 5
bezimeni [28]

Answer:

a.) 1.453MW/m2,  b.)  2,477,933.33 BTU/hr  c.) 22,733.33 BTU/hr  d.) 1,238,966.67 BTU/hr

Explanation:

Heat flux is the rate at which thermal (heat) energy is transferred per unit surface area. It is measured in W/m2

Heat transfer(loss or gain) is unit of energy per unit time. It is measured in W or BTU/hr

1W = 3.41 BTU/hr

Given parameters:

thickness, t = 7.5mm = 7.5/1000 = 0.0075m

Temperatures 150 C = 150 + 273 = 423 K

                        50 C = 50 + 273 = 323 K

Temperature difference, T = 423 - 323 = 100 K

We are assuming steady heat flow;

a.) Heat flux, Q" = kT/t

K= thermal conductivity of the material

The thermal conductivity of brass, k = 109.0 W/m.K

Heat flux, Q" = \frac{109 * 100}{0.0075} = 1,453,333.33 W/m^{2} \\ Heat flux, Q" = 1.453MW/m^{2} \\

b.) Area of sheet, A = 0.5m2

Heat loss, Q = kAT/t

Heat loss, Q = \frac{109*0.5*100}{0.0075} = 726,666.667W

Heat loss, Q = 726,666.667 * 3.41 = 2,477,933.33 BTU/hr

c.) Material is now given as soda lime glass.

Thermal conductivity of soda lime glass, k is approximately 1W/m.K

Heat loss, Q=\frac{1*0.5*100}{0.0075} = 6,666.67W

Heat loss, Q = 6,666.67 * 3.41 = 22,733.33 BTU/hr

d.) Thickness, t is given as 15mm = 15/1000 = 0.015m

Heat loss, Q=\frac{109*0.5*100}{0.015} =363,333.33W

Heat loss, Q = 363,333.33 * 3.41 = 1,238,966.67 BTU/hr

5 0
3 years ago
Explain the Corona discharge?​
rosijanka [135]

Answer:

• Corona discharge means <u> </u><u>neutralization</u><u> </u><u>of</u><u> </u><u>charge</u><u> </u><u>action</u><u> </u><u>at</u><u> </u><u>a</u><u> </u><u>sharp</u><u> </u><u>point</u>

example; a pear shaped conductor, lightening conductor, van de graaf generator.

Explanation:

• In corona discharge, When a sharp conductor is placed somewhere in open space. The charges of opposite chrage attract the opposite ions in the air around that conductor.

• This increases the charge density and electric field intensity at the sharp point, this neutralises the charge at sharp point hence a discharge known as corona discharge occurs.

.

8 0
3 years ago
How may acres of land are estimated to be lost each day to development?
Law Incorporation [45]
175 acres per hour of agricultural land lost to development – 3 acres per minute.
3 0
3 years ago
Example for strengthening mechanism in single-phase material A. Dispersion strengthening B. Precipitation hardening C. Fiber str
Lena [83]

Answer:

Example for strengthening mechanism in single-phase material: Strain hardening- D.

3 0
3 years ago
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