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marusya05 [52]
3 years ago
10

The displacement of an oscillating mass is 0.004*sin(7t) meters. What is the peak amplitude of its velocity in meters/second?

Engineering
1 answer:
german3 years ago
8 0

Answer:

The peak amplitude velocity is found to be 0.028 m/s.

Explanation:

Given that the displacement of an oscillating mass is:

Displacement = x = 0.004 Sin(7t)

Now, to find out the velocity of this particle, me have to take derivative of 'x' with respect to 't'.

Velocity = V = dx/dt = (7)(0.004)Cos (7t)

V = 0.028 Cos (7t)

Now, for the maximum displacement, the value of the Cos function must be maximum. And we know that the maximum value of Cos function is 1. Thus, to get maximum displacement, we set the value of Cos (7t) to be equal to 1.

Vmax = 0.028(1)

<u>Vmax = 0.028 m/s</u> (Peak Amplitude of Velocity)

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Answer: Technician A

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<u>Explanation: </u>

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Answer:

C++ code explained below

Explanation:

Please note the below program has been tested on ubuntu 16.04 system and compiled using g++ compiler. This code will also work on other IDE's

-----------------------------------------------------------------------------------------------------------------------------------

Program:

-----------------------------------------------------------------------------------------------------------------------------------

//header files

#include<iostream>

//namespace

using namespace std;

//function defintion

void Output_Array_Info(int *array_ptr, int size)

{

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{

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{

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}

}

//start of main function

int main()

{

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//end of the main program

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Answer:

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Hope this helped! :)

Explanation:

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