Answer: B, repetitive practice! hope this helps. :)
Explanation:
External depreciation may be defined as a loss in value caused by an undesirable or hazardous influence offsite.
<h3>What is depreciation?</h3>
Depreciation may be defined as a situation when the financial value of an acquisition declines over time due to exploitation, fray, and incision, or obsolescence.
External depreciation may also be referred to as "economic obsolescence". It causes a negative influence on the financial value gradually.
Therefore, it is well described above.
To learn more about Depreciation, refer to the link:
brainly.com/question/1203926
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Answer:
def theRoundTrip(movement):
x=0
y=0
for i in movement:
if i not in ["U","L","D","R"]:
print("bad input")
return
if i=="U":
y+=1
if i=="L":
x-=1
if i=="D":
y-=1
if i=="R":
x+=1
return x==0 and y==0
Answer:
diameter of the sprue at the bottom is 1.603 cm
Explanation:
Given data;
Flow rate, Q = 400 cm³/s
cross section of sprue: Round
Diameter of sprue at the top
= 3.4 cm
Height of sprue, h = 20 cm = 0.2 m
acceleration due to gravity g = 9.81 m/s²
Calculate the velocity at the sprue base
= √2gh
we substitute
= √(2 × 9.81 m/s² × 0.2 m )
= 1.98091 m/s
= 198.091 cm/s
diameter of the sprue at the bottom will be;
Q = AV = (π
/4) × 
= √(4Q/π
)
we substitute our values into the equation;
= √(4(400 cm³/s) / (π×198.091 cm/s))
= 1.603 cm
Therefore, diameter of the sprue at the bottom is 1.603 cm