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Jet001 [13]
3 years ago
8

A laptop computer is purchased for $1550 . after each year, the resale value decreases by 25% . what will the resale value be af

ter 3 years?
Mathematics
1 answer:
stich3 [128]3 years ago
3 0
The resale value after 3 years would be 387.50. Hope this helps!
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Beth plays a video game in which she starts with 0 points. In round 1 she loses 3 1/2 points; in round 2 she wins 28 1/2 points;
balu736 [363]
Her final score should be 21. You can add both 3 1/2 and 3 1/2 which will give you 7. Then substract it from 28. 
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3 years ago
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modal is made out of a stack of plywood sheets, each sheet is 0.6 inch thick. how many sheets of plywood tall is the modal ?
Montano1993 [528]
First what you need to do is 4.2 x 0.6 and that will be you answer.
7 0
3 years ago
Please Help ill make brainliest 15 points<br><br> A:149<br> B:153<br> C:225<br> D:297
pogonyaev

Answer: 225 square feet

Step-by-step explanation:

We find the area of the 4 triangle and the area of the rectangle and thereafter we add everything together.

Area of triangle 1 = 1/2 base × height

= 1/2 × 12 × 8

=96/2

=48

Area of triangle 2 = area of triangle 1= 48( because the opposite triangle are congruent so they have equal base and height)

Area of triangle 3 = 1/2×base×height

= 1/2 × 6 ×9.5

= 57/2

=28.5

Area of triangle 4=Area of triangle 3 = 57 (the opposite triangle are congruent and so they have the same base and height hence the same area)

Area of the rectangle = length×breadth

=12 × 6 =72

Total surface area = addition of all the areas of the triangles and the rectangle

Total surface area= 48+48+57+57+72 = 225

Therefore, the total surface area is 225 square feet

6 0
3 years ago
What is 109 divided by 8
Lelu [443]
 109 \div 8 

= 13.625
7 0
3 years ago
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lim x rightarrow 0 1 - cos ( x2 ) / 1 - cosx The limit has to be evaluated without using l'Hospital'sRule.
zaharov [31]

Answer with Step-by-step explanation:

Given

f(x)=\frac{1-cos(2x)}{1-cos(x)}\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-(cos^2{x}-sin^2{x})}{1-cos(x)})\\\\(\because cos(2x)=cos^2x-sin^2x)\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-cos^2x}{1-cos(x)}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}(\frac{(1-cosx)(1+cosx)}{1-cosx}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}((1+cosx)+\frac{sin^2x}{1-cosx})\\\\\therefore \lim_{x \rightarrow 0}f(x)=1

6 0
3 years ago
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