Answer:
(a+2)(b+2) = 4
Step-by-step explanation:
We are given the following quadratic equation:

Let a a and b be the solution of the given quadratic equation.
Solving the equation:

We have to find the value of (a+2)(b+2).
Putting the values:

Answer:
84 days
Step-by-step explanation:
You would use the LCM to solve this.
12 and 7 don't share any common factors other than 1,
so you would multiply 12 x 7, which gets you 84.
After 84 days they would have raised the same amount.
Let x = width
<span>length is 8 cm more than three times it’s width so length = 3x + 8
</span>
Perimeter of a rectangle = 2(L + W)
so
128 = 2(x + 3x + 8) solve for x (width)
128 = 2(4x + 8)
64 = 4x + 8
4x = 56
x = 14
width = 14 cm
length = 3(14) + 8 = 50 cm
Answer:
width = 14 cm
length = 50 cm
Answer:
(8,-3)
Step-by-step explanation:
The given parabola is

We factor -3 from the first two terms to get:

Add and subtract the square of half the coefficient of x


We simplify to get:

We compare this to y=a(x-h)²+k,
The vertex is (h,k)=(8,-3)
7y 4x and 2x they all are paired with a variable