Divide 5 by 6 to get0.8333 ( the 3 keeps repeating)
Answer: A & C
<u>Step-by-step explanation:</u>
HL is Hypotenuse-Leg
A) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH
a leg from ΔABC ≡ a leg from ΔFGH
Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH
B) a leg from ΔABC ≡ a leg from ΔFGH
the other leg from ΔABC ≡ the other leg from ΔFGH
Therefore LL (not HL) Congruency Theorem can be used.
C) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH
at least one leg from ΔABC ≡ at least one leg from ΔFGH
Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH
D) an angle from ΔABC ≡ an angle from ΔFGH
the other angle from ΔABC ≡ the other angle from ΔFGH
AA cannot be used for congruence.
Answer:
thats so deep
<em>i</em><em> </em><em>see</em><em> </em><em>where</em><em> </em><em>you</em><em> </em><em>are</em><em> </em><em>coming</em><em> </em><em>from</em><em> </em><em>and</em><em> </em><em>i</em><em> </em><em>see</em><em> </em><em>ur</em><em> </em><em>point</em>
<em>ppljust</em><em> </em><em>need</em><em> </em><em>to</em><em> </em><em>stop</em><em> </em><em>being</em><em> </em><em>selfish</em><em> </em><em>an</em><em> </em><em>helo</em><em> </em><em>eachother</em><em> </em><em>wetre</em><em> </em><em>in</em><em> </em><em>a</em><em> </em><em>pandemic</em><em> </em><em>for</em><em> </em><em>christs</em><em> </em><em>sake</em>
Answer:
47.0
Step-by-step explanation:
In this right angle triangle, we are faced with a challenge of two sides. The opposite side and the adjacent side, hence the tangent is used.
Where it is the opposite side and hypothenus side, the sine is used and when it is the hypothenus side and adjacent side, the cosine is used.
Hence, we have tan62°=x/25
We cross multiply, to have
25(tan 62°)= x
x = 47.01816
In rounding up numbers, number 1 to 4 will be rounded up to zero, while numbers 5 to 9 will be rounded up to 1.
Rounding up 47.01816 to the nearest tenth. The tenth value is the figure is 0, before it we have 1, which is to hundredth. 1 will be rounded up to zero.
So we have 47.0
