Option B:
Both n and m must be rational.
Solution:
Given information:
Sum of two numbers, n and m are rational.
<u>To find which statements are true:</u>
Option A: Both n and m may be rational but do not have to be.
It is not true because n and m given is rational.
It have to be rational.
Option B: Both n and m must be rational.
Yes, n and m must be rational then only the sum of numbers are rational.
It is true.
Option C: Both n and m must be irrational.
Sum of irrationals will be sometimes irrational and sometimes can't add.
So it is not true.
Option D: One number is rational and the other is irrational.
Rational and irrational cannot be add.
So it is not true.
Option B is true.
Both n and m must be rational.
Answer:
third graph
Step-by-step explanation:
We represent the above information in a two way frequency table.
Have Snowboarded Never Snawboarded Total
Skateboard 35 64 99
No Skateboard 13 147 160
Total 48 211 259
Therefore, the third graph is the correct answer.
Answer:
Step-by-step explanation:
what grade are you in so i can help
Answer:
0.1507 or 15.07%.
Step-by-step explanation:
We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters.
First of all, we will find z-scores for data points using z-score formula.
, where,
z = z-score,
x = Sample score,
= Mean,
= Standard deviation.
Let us find z-score of data point 22.03.
Using probability formula 
, we will get:
Therefore, the probability that a randomly selected ball bearing will be acceptable is 0.1507 or 15.07%.
3/2x + 1/5 >= -1
3/2x >= - 6/5
x >= -12/15
x >= -4/5
-1/2x - 7/3 >= 5
-1/2x >= 22/3
x <= -44/3
Its D
