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Lana71 [14]
3 years ago
9

Jenny walked around the football field which statement explains whether the example describes area or perimeter

Mathematics
1 answer:
e-lub [12.9K]3 years ago
5 0

Answer:

perimeter

Step-by-step explanation:  If she walks around its perimeter.  If she covers every inch of ground covered by the field its area.

Perimeter would be like an outline.  And area would be the whole thing shaded.  

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Find the part of the number.<br><br><br> * Find 3 1/16 of 32.
oee [108]

Answer:

98

Step-by-step explanation:

6 0
3 years ago
Simplify the expression.
spayn [35]

Answer:

C. \huge\frac{1}{3x {y}^{2}  {z}^{4}}

Step-by-step explanation:

(9 {x}^{2}  {y}^{4}  {z}^{8} )^{  - \frac{1}{2} }  \\   \\  = ( {3}^{2}  {x}^{2}  {y}^{4}  {z}^{8} )^{  - \frac{1}{2} }  \\  \\  =  \frac{1}{( {3}^{2}  {x}^{2}  {y}^{4}  {z}^{8} )^{ \frac{1}{2} }}  \\  \\  =  \frac{1}{(3x {y}^{2}  {z}^{4})^{2 \times  \frac{1}{2} }  }  \\  \\  =  \frac{1}{3x {y}^{2}  {z}^{4}} \\  \\  \red{ \bold{ \therefore \: (9 {x}^{2}  {y}^{4}  {z}^{8} )^{  - \frac{1}{2} } =  \frac{1}{3x {y}^{2}  {z}^{4}} }}\\

7 0
3 years ago
Wind farm configuration is a significant issue as the upwind turbines generate maximal energy while creating wakes for downwind
lord [1]

Answer:

a) [24.114,29.2858]

b) Since 30 is not in the 95% confidence interval, there is a 95% probability that 30 is not the true mean WEP

Step-by-step explanation:

a)

The 95% confidence interval is given by the interval

\bf [ \bar x-z^*\frac{s}{\sqrt n}, \bar x+t^*\frac{s}{\sqrt n}]

where

\bf \bar x= 26.7 is the sample mean  

s = 17.7 is the sample standard deviation  

n = 180 is the sample size

Since the sample size is big enough, we can use the Normal N(0,1) to compute \bf z^* and it would be 1.96(*) (a value such that the area under the Normal curve outside the interval [-z, z] is 5% (0.05))

and our 95% confidence interval is

\bf [26.7-1.96*\frac{17.7}{\sqrt{180}}, 26.7+1.96*\frac{17.7}{\sqrt{180}}]=\boxed{[24.114,29.2858]}

(*)

This value can be computed in Excel with

<em>NORMINV(1-0.025,0,1)</em>

and in OpenOffice Calc with

<em>NORMINV(1-0.025;0;1)</em>

b)

Since 30 is not in the 95% confidence interval, there is a 95% probability that 30 is not the true mean WEP

7 0
3 years ago
This bag has an unknown number of lollipops and jelly snakes in it. I know that Pr (jelly snake) = 4/5. How many jelly snakes co
juin [17]

Answer:

40.

Step-by-step explanation:

Let J represent jelly snake.

Let L represent lollipops

Let S represent sample space

Let y represent the number of jelly snake in the bag. I.e

Number of J = y

Number of L = 10

Number of S = 10 + y

From the question given, we were told that the probability of jelly snake P(J) is 4/5.

But probability of jelly snake, P(J) is given by:

P(J) = nJ/nS

nJ = y

nS = 10 + y

P(J) = 4/5

Thu, we can obtain the number jelly snake, y, in the bag as follow:

P(J) = nJ/nS

4/5 = y/(10 + y)

Cross multiply

5y = 4(10 + y)

Clear bracket

5y = 40 + 4y

Collect like terms

5y – 4y = 40

y = 40

Therefore, the number of jelly snake in the bag is 40

8 0
3 years ago
1. Which of the following is equivalent to x5y2/xy2 when x ≠ 0 and y ≠ 0?
Aleonysh [2.5K]
Q1. The answer is <span>D. x4
</span>
Let's first rewrite the expression:
x⁵y²/xy² = x⁵/x * y²/y²

Using the rule xᵃ/xᵇ = x(ᵃ⁻ᵇ), we can write the expression as following:
x⁵y²/xy² = x⁵/x * y²/y² = x⁵⁻¹ * y²⁻² = x⁴ * y⁰ = x⁴ * 1 = x⁴

Thus, the correct answer is D.


Q2. The answer is <span>A. 5(5^3/2/5)^2
</span>
125 in the form of exponent is 5³.
125 = 5³
Now, let's calculate all choices. 
 
The rules we will use are:
xᵃ * xᵇ = x(ᵃ⁺ᵇ)
xᵃ/xᵇ = x(ᵃ⁻ᵇ)
(xᵃ)ᵇ = xᵃ*ᵇ

A. 5(5³/2/5)² = 5 * (5³ * 5/2)²
                      = 5 * (5³⁺¹/2)²
                      = 5 * (5⁴/2)²
                      = 5 * (5⁴)²/(2)²
                      = 5 * 5⁴*²/4
                      = 5 * 5⁸ / 4
                      = 5¹⁺⁸ / 4
                      = 5⁹/4
                      ≠ 5³ ≠ 125

B. (5³/5⁴)⁻³ = (5³⁻⁴)⁻³
                   = (5⁻¹)⁻³
                   = 5⁽⁻¹⁾*⁽⁻³⁾
                   = 5³
                   = 125

C. 5⁻²/5⁻⁵  = 5⁽⁻²⁾⁻⁽⁻⁵) 
                  = 5⁽⁻²⁾⁺⁵
                  = 5³
                  = 125<span>

D. 5(5</span>⁵/5³) = 5 * 5⁵⁻³
                  = 5 * 5²
                  = 5¹⁺²
                  = 5³
                  = 125

Therefore, the only expression that is not equal to 125 is A.


Q3. The answer is <span>63x5

Let's check all choices
</span>The rules we will use are:
xᵃ * xᵇ = x(ᵃ⁺ᵇ)
xᵃ/xᵇ = x(ᵃ⁻ᵇ)
(xᵃ)ᵇ = xᵃ*ᵇ

A. 6³<span>x 
</span>6³x/6x⁵ = 6³/6 * x/x⁵
             = 6³⁻¹ * x¹⁻⁵
             = 6²x⁻⁴
             = 36x⁻⁴
             ≠ 36<span>

B. 6</span>³x⁵ 
6³x⁵/6x⁵ = 6³/6 * x⁵/x⁵
              = 6³⁻¹ * x⁵⁻⁵
              = 6² * x⁰
<span>              = 36 * 1
              = 36

C. 6x</span>⁵<span> 
</span>6x⁵/6x⁵ = 1
             ≠ 36
<span>
D. 6</span>⁷x⁵
6⁷x⁵/6x⁵ = 6⁷/6 * x⁵/x⁵
              = 6⁷⁻¹ * x⁵⁻⁵
              = 6⁶ * x⁰
              = 46656 * 1
              ≠ 36

Therefore, the correct choice is B.


Q4. The answer is

We will use the rule: xᵃ/xᵇ = x(ᵃ⁻ᵇ)

5.4 x 10¹²/1.2 x 10³ = 5.4 / 1.2 x 10¹²/10³
                               = 4.5 x 10¹²⁻³
                               = 4.5 x 10⁹


Q5. The answer is B. <span>To subtract powers with the same base, divide the exponents

Some of the rules </span><span>regarding operations with exponents are:
</span>xᵃ/xᵇ = x(ᵃ⁻ᵇ) - choice A
xᵃ * xᵇ = x(ᵃ⁺ᵇ) - choice C
(xᵃ)ᵇ = xᵃ*ᵇ - choice D

Through the process of elimination, choice B is not true.
8 0
3 years ago
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