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3 years ago

10

a bag contains 6 blue marbles, 10 red marbles, and 9 green marbles if two marbles are drawn at random without replacement what i

s the probability that two green marbles are drawn

1 answer:

Papessa [141]3 years ago

3 0

P ( first one drawn is green) = 9 /25

P(second drawn is green) = 8/24 = 1/3

Probabilty both green = 9/25 * 1/3 = 9/75 = 3/25 answer

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Free_Kalibri [48]

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3 years ago

Read 2 more answers

Help me please. I'm very confused

aliya0001 [1]

To solve this problem we must find 5% of 1418 and 4% of 1418
which is
$5 \div 100 \times 1418 \\ \ \\ 4 \div 100 \times 1418$

so that would be 70.9 house extra in the first year and 56.72 extra in the second year respectively.
so to find the total number of houses we must add 70.9 + 56.72 + 1418 which gives us 1545.62
at the last it is mentioned for us to round our answer to the nearest

they are asking us for the total number whole number
which is 1546
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3 years ago