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denis-greek [22]
3 years ago
12

Pro

Mathematics
1 answer:
Firdavs [7]3 years ago
8 0

Answer:

C. Both (1, 11) and (-1, -5)

Step-by-step explanation:

The missing options are:

<em> A. Only (1, 11) </em>

<em>B. Only (-1, -5)  </em>

<em>C. Both (1, 11) and (-1, -5) </em>

<em>D. Neither </em>

To check if an ordered pair is a solution of an equation, replace one variable into the equation an calculate the other one.

Replacing x = 1, we get:

y = 8(1) + 3

y = 11

then (1, 11) is a solution

Replacing x = -1, we get:

y = 8(-1) + 3

y = -5

then (-1, -5) is a solution

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It's in the equation

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yes.<em> </em><em>2</em><em> </em><em>is</em><em> </em><em>an</em><em> </em><em>only</em><em> </em><em>even</em><em> </em><em>prime</em><em> </em><em>number</em><em>. </em>

Step-by-step explanation:

<em>Prime</em><em> </em><em>number</em><em> </em><em>means</em><em> </em><em>a</em><em> </em><em>number</em><em> </em><em>that</em><em> </em><em>can</em><em> </em><em>be</em><em> </em><em>exactly</em><em> </em><em>divisible</em><em> </em><em>by</em><em> </em><em>1</em><em> </em><em>and</em><em> </em><em>itself</em><em> </em><em>is</em><em> </em><em>called</em><em> </em><em>prime</em><em> </em><em>number</em><em>. </em>

<em>2</em><em> </em><em>is</em><em> </em><em>divisible</em><em> </em><em>by</em><em> </em><em>1</em><em> </em><em>and</em><em> </em><em>2</em>

<em>prime</em><em> </em><em>number</em><em> </em><em>has</em><em> </em><em>only</em><em> </em><em>two</em><em> </em><em>factors</em><em>. </em>

<em>FOR</em><em> </em><em>Example</em><em>:</em><em> </em><em>13</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

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