Answer:
1) By SAS theorem, ΔADE≅ΔCDF
2) By SSS theorem, ΔBDE≅ΔBDF
Step-by-step explanation:
Consider isosceles triangle ABC (see diagram).
1. In triangles ADE and CDF:
- AD≅DC (since BD is median, then it divides side AC in two congruent parts);
- AE≅CF (given);
- ∠A≅∠C (triangle ABC is isosceles, then angles adjacent to the base are congruent).
By SAS theorem, ΔADE≅ΔCDF.
2. In triangles BDE and BDF:
- side BD is common;
- DE≅DF (ΔADE≅ΔCDF, then congruent triangles have congruent corresponding sides);
- BE≅FB (triangle ABC is isosceles, AB≅BC, AE≅CF, then BE=AB-AE, FB=BC-CF).
Be SSS theorem, ΔBDE≅ΔBDF.
The hypotenuse angle theorem<span> basically states that if the hypotenuse and an acute angle of one right triangle</span><span> are congruent to the </span>hypotenuse<span> and an acute </span>angle<span> of another right triangle, then the two triangles are congruent.
So I would say D is correct</span>
Answer:
stack AD with bar on top space text is parallel to end text BC with bar on top.
204 times .46 equals 93.84, to round of it would be 93.8
P = 2(L + W)
P = 44
L = W + 2
44 = 2(W + 2 + W)
44 = 2(2W + 2)
44 = 4W + 4
44 - 4 = 4W
40 = 4W
40/4 = W
10 = W
L = W + 2
L = 10 + 2
L = 12
A = L * W
L = 12
W = 10
A = 12 * 10
A = 120 square inches <===
