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Alisiya [41]
3 years ago
13

80 POINTS !!

Mathematics
1 answer:
givi [52]3 years ago
6 0

Answer:

-4x^3+x+7

Step-by-step explanation:

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What should the IUPAC name for a binary covalent compound lack? prefixes Roman numerals an -ide ending the name of a nonmetal.​
vitfil [10]

The  IUPAC name for a binary covalent compound lack prefixes such as mono, di, tri tetra etc.

A binary compound is a compound that is composed of only two elements. Many binary compounds could be made up of a metal and a nonmetal or even two nonmetals as the case may be. Examples of binary compounds include; SO2, NaH, K2S etc.

We must note that a binary covalent compound uses Roman numerals to indicate the oxidation state of the central atom in the compound. For instance, SO2 is called Sulfur IV oxide.

Hence, the  IUPAC name for a binary covalent compound lack prefixes such as mono, di, tri tetra etc.

Lear more about IUPAC: brainly.com/question/11587934

5 0
2 years ago
Find the volume of each figure. Round to the nearest tenth if necessary.​
ziro4ka [17]

Answer:

112

Step-by-step explanation:

The volume is given by l*b*h=4*4*7=112

7 0
3 years ago
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
Lapatulllka [165]

Answer:

Step-by-step explanation:

Given that there is a function of x,

f(x) = 2sin x + 2cos x,0\leq x\leq 2\pi

Let us find first and second derivative for f(x)

f'(x) = 2cosx -2sinx\\f"(x) = -2sinx-2cosx

When f'(x) =0 we have tanx = 1 and hence

a) f'(x) >0 for I and III quadrant

Hence increasing in (0, \pi/2) U(\pi,3\pi/2)\\

and decreasing in (\pi/2, \pi)U(3\pi/2,2\pi)

x=\frac{\pi}{4}, \frac{3\pi}{4}

f"(\pi/4)

Hence f has a maxima at x = pi/4 and minima at x = 3pi/4

b) Maximum value = 2sin \pi/4+2cos \pi/4 =2\sqrt{2}

Minimum value = 2sin 3\pi/4+2cos 3\pi/4 =-2\sqrt{2}

c)

f"(x) =0 gives tanx =-1

x= 3\pi/4, 7\pi/4

are points of inflection.

concave up in (3pi/4,7pi/4)

and concave down in (0,3pi/4)U(7pi/4,2pi)

3 0
3 years ago
In expansion of (2x+1)(x^2+px+4), the coefficient of x is twice the coefficient of x^2.
Brilliant_brown [7]

You're probably supposed to find the value of p and not x, which is impossible to do.

Expanding gives

(2x+1)(x^2+px+4)=2x^3+(1+2p)x^2+(8+p)x+4

We're told that

8+p=2(1+2p)

which we can use to solve for p:

8+p=2+4p

6=3p

\boxed{p=2}

7 0
3 years ago
Why does the pressure go down when the velocity of a fluid increase?<br> Please help asap!
Hunter-Best [27]

Answer:It is the conversion of one form of energy to another. If a fluid flow is restricted, the velocity of the fluid reduces, thereby the kinetic energy decreases and the equivalent amount of energy is increased as the pressure energy, which therefore increases the point pressure of the fluid.

Step-by-step explanation:

7 0
2 years ago
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