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hram777 [196]
3 years ago
10

Given that a=25, b=43 and c=17 solve triangle ABC

Mathematics
1 answer:
Montano1993 [528]3 years ago
3 0
The given lengths cannot form a triangle. They do not meet the requirements of the triangle inequality.

17 + 25 < 43
The triangle inequality requires each side be shorter than the sum of the other two.

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Which fraction is equivalent to 1/6?
Elanso [62]

Answer:

There could be many answers: 2/12, 3/18, 4/24...

Step-by-step explanation:

You never really gave options but all you do is just take 1/6 and multiply the top and bottom by a certain number to get what you're looking for, for example 1/6 times 2, both on the top and bottom will get you 2/12 because 1 times 2 is 2 and, 6 time 2 is 12. :)

5 0
3 years ago
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Help me please this is dew by the end of the day
german

Answer:x = 4 1/2

19-2 1/2 x2 = 14-2 1/2 x2 = 9/2 = 4 1/2

3 0
3 years ago
How many tiles are in figure 100?<br> .<br> Figure 1<br> Figure 2<br> Figure 3
Ilia_Sergeevich [38]

Answer:

202

Step-by-step explanation:

in\\\\F(1)=4\:dots\\\\F(2)=F(1)+2=4+2=6\:dots\\\\F(3)=F(2)+2=F(1)+2+2=F(1)+2(2)=8\:dots\\\\As\:you\:can\:see\:in\\\\F(n)=F(1)+2(n-1)\\\\So\:with\:n=100\\\\F(100)=F(1)+2(100-1)\\\\F(100)=4+2(100)+2(-1)\\\\F(100)=4+200-2\\\\F(100)=200+2\\\\F(100)=202

3 0
3 years ago
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Solve the following differential equation: y" + y' = 8x^2
PtichkaEL [24]

Answer:

y=y_p+y_h = \frac{8}{3}x^3-8x^2+16x+ C_1 + C_2e^{-x}

Step-by-step explanation:

Let's  find a particular solution. We need a function of the form y= ax^3+bx^2+cx+d such that

y'= 3ax^2+2bx+c and

y''= 6ax+2b

y'+y''= 3ax^2+2bx+c+6ax+2b = 3ax^2+x(2b+6a)+(c+2b) = 8x^2

then, 3a= 8, 2b+6a =0 and c+2b = 0. With the first equation we obtain

a =  8/3 and replacing in the second equation 2b+6(8/3) = 2b + 16 = 0. Then, b = -8. Finally, c = -2(-8) = 16.

So, our particular solution is  y_p= \frac{8}{3}x^3-8x^2+16x.

Now, let's find the solution y_p of the homogeneus equation y''+y'=0 with the method of constants coefficients. Let y=e^{\lambda x}

y'=\lambda e^{\lambda x}

y''=\lambda^2e^{\lambda x}

then \lambda e^{\lambda x}+\lambda^2 e^{\lambda x} = 0

e^{\lambda x}(\lambda +\lambda^2)= 0

(\lambda +\lambda^2)= 0

\lambda (1+\lambda)= 0

\lambda =0 and \lambda)= -1.

So, y_h = C_1 + C_2e^{-x} and the solution is

y=y_p+y_h =\frac{8}{3}x^3-8x^2+16x+ C_1 + C_2e^{-x}.

5 0
3 years ago
95/8 -17/8 what does it equal
Rufina [12.5K]
Input the fraction = 95/8 
Integer =11
Fraction part = 7/8
Answer = 11.875
8 0
3 years ago
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