Answer:
32
Step-by-step explanation:
Totally there are 50 tosses.
Let the number of tosses which resulted head be x.
Therefore the number of tosses which resulted tail is 50−x.
We get x×1+(50−x)×(−1)=14
x−(50−x)=14
x−50+x=14
x=32
Answer:
n + 4
Step-by-step explanation:
It´s like a normal sum, but since the number is unknown just put n.
Probability helps us to know the chances of an event occurring. The probability being a Sophomore given she is a girl is 1/3.
<h3>What is Probability?</h3>
Probability helps us to know the chances of an event occurring.
The probability of being a girl and Sophomore is 9/37. While the probability of being a girl is 27/37. Therefore, the probability being a Sophomore given she is a girl is,
P(Girl l Sophomores) = P(Girl and Sophomore)/ P(Girl)
= (9/37) / (27/37)
= 9 / 27
= 1/3
Hence, the probability being a Sophomore given she is a girl is 1/3.
Learn more about Probability:
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Answer:
(0.5848 ; 0.6552)
We are confident that about 58% to 66% of sea foods in the country are Mislabelled.
No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.
Step-by-step explanation:
Sample size, n = 51
p = 0.62
1 - p = 1 - 0.62 = 0.38
n = 515
Confidence level = 90% = Zcritical at 90% = 1.645
Confidence interval = (p ± margin of error)
Margin of Error = Zcritical * sqrt[(p(1-p))/n]
Margin of Error = 1.645 * sqrt[(0.62(0.38))/515]
Margin of Error = 1.645 * 0.0214
Margin of Error = 0.035203
Lower boundary = (0.62 - 0.035203) = 0.584797
Upper boundary = (0.62 + 0.035203) = 0.655203
(0.5848 ; 0.6552)
We are confident that about 58% to 66% of sea foods in the country are Mislabelled.
No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.
