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Sauron [17]
3 years ago
15

How long must a simple pendulum be if it is to make exactly one swing per three seconds? (that is, one complete oscillation take

s exactly 6.0 s.)?
Mathematics
1 answer:
Stolb23 [73]3 years ago
3 0
This is a physics question.

Use the formula for simple pendulum:

T = 2π √(L/g)

Where T is the period (time to complete a full oscilation), L is the lenght and g acceleration of gravity ≈ 9.81 m/s^2 .

So, solve for l:

√(L/g) = T / (2π)

L = [T / (2π) ] ^2 * g = [ 6.0s / (2π) ]^2 * 9.81 m/s^2 = 8.9 m

Answer: 8.9 m
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8 baseballs : 4 gloves

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2 baseballs : 1 glove

10 baseballs : 5 gloves

Step-by-step explanation:

I think It's just asking to put some ratios that go with the one given.

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Find the volume of the cone. Round you’re answer to the nearest truth if necessary. Use 3.14
S_A_V [24]

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Step-by-step explanation:

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3 years ago
22nd term: 28, 23, 18, 13,..
Verizon [17]

Answer:

The 22nd Term is -77.

Step-by-step explanation:

The pattern is -5.  If you subtract 5 from each starting number you'll get the following number.

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       18 - 13  = 5

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I hope this was the most brainliest answer, thank you for letting me help you !

7 0
3 years ago
The rainfall total this year was 10.2 inches, which is 20%less the last year’s rainfall total. What was last year’s rainfall tot
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4 0
3 years ago
The head librarian at the Library of Congress has asked her assistant for an interval estimate of the mean number of books check
Verdich [7]

Answer:

n=(\frac{1.960(150)}{90})^2 =10.67 \approx 11

So the answer for this case would be n=11 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma =150 represent the population standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The confidence interval for this case is given by: (740, 920)

We can find the estimate for the mean and we got:

\bar X = \frac{740+920}{2} = 830

and the margin of error is given by :

ME = \frac{920-740}{2}= 90

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =90 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} s}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(150)}{90})^2 =10.67 \approx 11

So the answer for this case would be n=11 rounded up to the nearest integer

5 0
3 years ago
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