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Temka [501]
3 years ago
8

What is the square root of 109

{ 109 } " alt=" \sqrt{ 109 } " align="absmiddle" class="latex-formula">
​

Mathematics
1 answer:
Alex777 [14]3 years ago
7 0
10.44031 that’s the square route

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vredina [299]
The correct answer is A, if you use photomath you can usually find the answers to most algebra problems
4 0
3 years ago
Subtract 2xy-8 from 5x^2+3xy+12
JulijaS [17]

Answer:

5x^2 + xy + 20

Step-by-step explanation:

Begin with 5x^2+3xy+12,  Subtracting 2xy yields 5x^2 + xy + 12.  Next, subtracting -8 yields 5x^2 + xy + 12 - (-8), or   5x^2 + xy + 20

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2 years ago
Solve the equation for all values of x by completing the square.<br> x2 + 21 = 10x
sashaice [31]

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3 0
3 years ago
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4 tens and 10 ones is 410
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3 years ago
Find the equation of the line<br> Use exact numbers <br> y=*blank*x+*blank*
Murljashka [212]
You are looking for the slope and y intercept to complete the equation of the line.

The equation of a line is in something called slope intercept form. That looks like y = mx + b. m represents the slope (measure of how steep a line is, and in which direction it is going) and b represents the y intercept (y coordinate when x = 0). You need to find the slope and y intercept to complete the equation.

First, find the slope. The formula for slope is: m = (y2 - y1)/(x2 - x1) where m is the slope and (x1, y1) and (x2, y2) are points.

Pick any two points on the graph. I will use (-2, 0) and (0, 4). Now use these values to find the slope.

m = (4-0)/(0+2) = 4/2
m = 2

m = 2 means that for every two units the line goes up on the y axis, it moves one to the right on the x axis. 2 will go in your first box.

Now find the y intercept. The y intercept is where the line crosses the y axis - it is the y coordinate when x = 0. Here when x = 0, y = 4, so your y intercept is at 4. 4 goes into your second box.

The equation is y = 2x + 4

6 0
3 years ago
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