Create an equation using the formula for area of a rectangle; area = width * length
(X + 2)(x + 3) = 600
Multiply the dimensions.
X^2 + 3x + 2x +6 = 600, or simplified x^2 +5x + 6 = 600.
Subtract 600 to get the following:
X^2 + 5x - 594 = 0
Factor by x:
(X - 22)(x + 27) = 0
Solve for x
X - 22 = 0
X = 22.
Use the POSITIVE VALUE of x as you can’t have a negative area for a room.
Then substitute 22 for x to get the dimensions
(22+ 2) or 24 for length and (22+3) or 25 for width.
Answer: second option.
Step-by-step explanation:
Given the transformation
→
You must substitute the x-coordinate of the point A (which is
) and the y-coordinate of the point A (which is
) into
to find the x-coordinate and the y-coordinate of the image of the point A.
Therefore, you get that the image of A(2,-1) is the following:
You can observe that this matches with the second option.
Answer:
C. 15.6
Step-by-step explanation:
Perimeter of WXYZ = WX + XY + YZ + ZW
Use the distance formula,
to calculate the length of each segment.
✔️Distance between W(-1, 1) and X(1, 2):
Let,


Plug in the values





✔️Distance between X(1, 2) and Y(2, -4)
Let,


Plug in the values





✔️Distance between Y(2, -4) and Z(-2, -1)
Let,


Plug in the values





✔️Distance between Z(-2, -1) and W(-1, 1)
Let,


Plug in the values





✅Perimeter = 2.24 + 6.08 + 5 + 2.24 = 15.56
≈ 15.6
Answer:
4
Step-by-step explanation:
Let the number be x.
(11+41)/x = 13
52/x = 13
13x = 52
x = 52/13
x = 4