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vovikov84 [41]
2 years ago
11

Help me with math please.

Mathematics
1 answer:
djverab [1.8K]2 years ago
3 0
The answer to that will C and that is easy
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Ivenika [448]

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Please help quick.. I’ve been stuck on this no matter what answer I have
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Answer:

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Which is the equation of a hyperbola centered at the origin with y-intercepts +12 -12, and asymptote y=3x/2
dangina [55]

Answer:

\frac{y^2}{144}-\frac{x^2}{64}=1

Step-by-step explanation:

The equation of a hyperbola centered at the origin with vertices on the y-axis is given by: \frac{y^2}{a^2}-\frac{x^2}{b^2}=1

The vertices of the hyperbola are the y-intercepts (0,12) and (0,-12)

This implies that:

2a=|12--12|

2a=24

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The asymptote equation of a hyperbola is given by:

y=\pm\frac{a}{b}x

The given hyperbola has asymptote: y=\pm\frac{3}{2} x

By comparison; \frac{a}{b}=\frac{3}{2}

\implies \frac{12}{b}=\frac{12}{8}

\implies b=8

The required equation is:

\frac{y^2}{12^2}-\frac{x^2}{8^2}=1

Or

\frac{y^2}{144}-\frac{x^2}{64}=1

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