I'm honestly not really sure, but it has to be either (2,10) or (10,2). I've never seen a question like this...
Answer:
Step-by-step explanation:
Answer:
Ok, as i understand it:
for a point P = (x, y)
The values of x and y can be randomly chosen from the set {1, 2, ..., 10}
We want to find the probability that the point P lies on the second quadrant:
First, what type of points are located in the second quadrant?
We should have a value negative for x, and positive for y.
But in our set; {1, 2, ..., 10}, we have only positive values.
So x can not be negative, this means that the point can never be on the second quadrant.
So the probability is 0.
Answer:
d
Step-by-step explanation:
i did th etst hope it helps
The area of a triangle is A = (b*h)/2:
(5 * 8)/2 = 20