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Anit [1.1K]
3 years ago
11

In 1990, the price of a gallon of unleaded gasoline was $1.37. In 1998, it was $1.02 per gallon. What is the decrease expressed

as a percent change? Round to the nearest tenth of a percent if necessary.
Mathematics
1 answer:
mojhsa [17]3 years ago
7 0
The decrease is 35c

Q= X/100 of $1.37 = 0.35

1.37x/100 = 0.35

1.37x = 35 then divide each side by 1.37

Result is 25.5474453 percent, round up to nearest tenth.
Answer is 25%

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Step-by-step explanation:

9 + 2(14x - 3) = 19

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The 99% confidence interval for the mean commute time of all commuters in Washington D.C. area is (22.35, 33.59).

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha /2}\frac{\sigma}{\sqrt{n}}

Here the population standard deviation (σ) is not provided. So the confidence interval would be computed using the <em>t</em>-distribution.

The (1 - <em>α</em>) % confidence interval for population mean (<em>μ</em>) using the <em>t</em>-distribution is:

CI=\bar x\pm t_{\alpha /2,(n-1)}\frac{s}{\sqrt{n}}

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Compute the 99% confidence interval as follows:

CI=27.97\pm 2.797\times\frac{10.04}{\sqrt{25}}\\=27.97\pm5.616\\=(22.354, 33.586)\\\approx(22.35, 33.59)

Thus, the 99% confidence interval for the mean commute time of all commuters in Washington D.C. area is (22.35, 33.59).

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