All categories

3 years ago

1. What is the slope and the y-intercept for the

Mathematics

2 answers:

Usimov [2.4K]3 years ago

7 0

Answer:

Step-by-step explanation:

Slope= -5

y-intercept= 4

Simora [160]3 years ago

4 0

Answer:

the slope is -5 and the y intercept is (0,4)

Step-by-step explanation:

You might be interested in

STILL GOING BAN ON THEM ANYWAY

iren [92.7K]

Answer:

I-

Step-by-step explanation:

Um okay.

7 0

2 years ago

Read 2 more answers

Simplify this exponential expression:<br><br> (-49) 2/5

ioda

Answer:

I think it is 12 4/5

Step-by-step explanation:

hope this helps if not let me now

4 0

1 year ago

bryan has some 3 cent stamps and some 4 cent stamps. what is the least number of stamps he can combine so the value of the stamp

SashulF [63]

Answer:

The least number of stamps required is $9$

Step-by-step explanation:

Let the number of $3$ cent stamps be $x$ and $4$ cent stamps be $y$

We have

$3x+4y=33$

The minimum number is obtained when more $4$ cent stamps are used

Here $y$ cannot be greater than $8$ since $\frac{33}{4}$

Substitute $y=8$

$3x+4\times 8=33\\\\3x=1\\\\x=\frac{1}{3}$

Not possible since $x$ is not a fraction

Substitute $y=7$

$3x+4\times 7=33\\\\3x=5\\\\x=\frac{5}{3}$

Not possible since $x$ is not a fraction

Substitute $y=6$

$3x+4\times 6=33\\\\3x=9\\\\x=\frac{9}{3}\\\\=3$

Possible

Hence minimum number of stamps is

$=x+y\\\\=3+6\\\\=9$

5 0

2 years ago

Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean

Zinaida [17]

Answer:

$E[R]$ = 99 Ω

$\sigma_R$ = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, $E[R] = \frac{a+b}{2} = \frac{95+103}{2} = \frac{198}{2}$ = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

$V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333$

Hence,

The standard deviation of resistance, $\sigma_R = \sqrt{V(R)} = \sqrt5.333$ = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

$z_1 = \frac{102-99}{2.3094} = 1.299$

$z_2 = \frac{98-99}{2.3094} = -0.433$

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0

3 years ago

What is -7/12 + 3/8?

inna [77]

Answer:

- $\frac{5}{24}$

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers