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gulaghasi [49]
4 years ago
9

Eliza’s parents are installing an above ground swimming pool in their backyard. The pool is a right circular cylinder with a dia

meter of 18 feet and a height of 7 feet.
Once her parents fill the pool, it will have a depth of 6 feet. What is the volume of water, to the nearest cubic foot, that will be in the pool once it is filled.
(The volume, V, of a right circular cylinder with radius r and height h is given by the formula)
F. 170
G. 1,527
H. 1,781
j. 2,375
K. 6,107

Mathematics
1 answer:
steposvetlana [31]4 years ago
6 0

Answer:

H = 1781

Step-by-step explanation:

First, find the radius which is 9; 18/2. Then use cyclinder formula pi*r^2*h. Substitute values, but replace height with 6 because you are finding volume of water. Equation: pi*9^2*6

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Stolb23 [73]

Answer:

The Base is 150 and the Exponent is 4

8 0
3 years ago
Someone please help​
svp [43]

Answer:

I got 25z^2−15z+2

Step-by-step explanation:

But if the answer shown is the correct answer, I think your computer read wrong, because those answers are the exact same :/

7 0
3 years ago
Read 2 more answers
Laura, Scott, and Joe served a total of 104
umka21 [38]

9514 1404 393

Answer:

  • Joe: 57
  • Scott: 19
  • Laura: 28

Step-by-step explanation:

Let s represent the number of orders Scott served. Then we have Joe served 3s, and Laura served (s+9). The total of orders served is ...

  3s +s +(s +9) = 104

  5s = 95 . . . . . . . . . . . subtract 9 and collect terms

  s = 19 . . . . . . . . . divide by 5

  3s = 3×19 = 57

  s+9 = 19+9 = 28

Joe served 57 orders, Scott served 19, and Laura served 28 orders.

3 0
3 years ago
14 2/7 % simplest form
KATRIN_1 [288]
14 x 7 = 98 and then add the 2 = 100/7 

3 0
3 years ago
3y+10x-54=0 5y-2x-34=0<br><br> x=<br><br> y=
Blababa [14]
<h3>Answer:</h3><h2>x = 3 and y = 8 → (3, 8)</h2><h3>Step-by-step explanation:</h3>

\left\{\begin{array}{ccc}3y+10x-54=0&\text{add 54 to both sides}\\5y-2x-34=0&\text{add 34 to both sides}\end{array}\right\\\left\{\begin{array}{ccc}3y+10x=54\\5y-2x=34&\text{multiply both sides by 5}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}3y+10x=54\\25y-10x=170\end{array}\right}\ \ \ \ |\text{add both sides of the equations}\\.\ \ \ \ \ 28y=224\qquad\text{divide both sides by 28}\\.\ \ \ \ \ \ \ \dfrac{28y}{28}=\dfrac{224}{28}\\.\ \ \ \ \ \ \ \boxed{y=8}

\text{put the value of y to the first equation}\\\\3(8)+10x=54\\24+10x=54\qquad\text{subtract 24 from both sides}\\24-24+10x=54-24\\10x=30\qquad\text{divide both sides by 10}\\\dfrac{10x}{10}=\dfrac{30}{10}\\\boxed{x=3}

8 0
3 years ago
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