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Mumz [18]
3 years ago
14

A waste collection tank can hold 18754 kg of methanol, which has a density of 0.788 g/cm3.

Chemistry
1 answer:
quester [9]3 years ago
3 0
Given:
Mass of methanol, m = 18754 kg
Density of methanol, ρ = 0.788 g/cm³

By definition, the volume of methanol in the collection tank is
Volume  = mass/density
               = \frac{(18754 \, kg)*(10^{3} \,  \frac{g}{kg}) }{(0.788 \,  \frac{g}{cm^{3})} }  \\ \\ =2.38 \times 10^{7} \,  \frac{g}{cm^{3}}

Answer:  2.38 x 10⁷ g/cm³
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