Answer:
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Answer: True
Explanation: Specific Gravity of a body, also called its Relative Density, is the ratio of the density of that body to the density of a reference material (usually water).
With the Mathematics done right, it is evident that the specific gravity of a body would be equal to the ratio of mass/weight of the body to the mass/weight of an equal volume of water.
S.G = (Density of body)/(Density of water)
Density of Body = (mass/weight of body)/(volume of body)
Density of water = (mass/weight of water)/(volume of water)
If volume of Body = Volume of water, then,
S.G = (Mass/Weight of body)/(Mass/Weight of equal volume of water)
Proved!!
There’s only one measurement the question doesn’t make sense
Answer:
Neutralization
Explanation:
When an acid react with base it form the salt and water. The reaction is also called neutralization reaction because both neutralize each other.
In neutralization reaction equal amount of acid and base react to neutralize each other and equal amount of water and salt are formed. When pH does not reach to 7 its means there is less amount of one of reactant which is not fully neutralize.
Neutralization reactions are also used as first aid. For example when someone is dealing with HCl for cleaning purpose of toilet and get touched. It is advised to neutralize it with soap, milk or egg white.
Example:
Hydrochloric acid when react with the sodium hydroxide, a salt sodium chloride and water are formed.
Chemical equation:
HCl + NaOH → NaCl + H₂O
Titration:
Neutralization reactions are also used to determine the concentration of solution. Titration is a quantitative technique in which acid or base is gradually added into the solution whose concentration is to be determine until the neutral point is reached.
Answer:
12 moles of H₂O are formed in this combustion.
Explanation:
First of all, think the reaction:
2CH₃OH (l) + 3O₂ (g) → 2CO₂ (g) + 4H₂O (g)
Ratio in the reactants is 2:3, so 2 mol of methanol need 3 mol of oxygen to react. Then 8 mol of CH₃OH, will need (8.3)/2 = 12 moles of O₂
We have 9 moles of O₂, so this is the limiting reactant.
3 mol of oxygen produce 4 mol of water
Then, 9 mol of oxygen will produce ( 9 .4)/3 = 12 moles
