The classic Periodic Table<span> organizes the chemical </span>elements<span> according to the </span>number of<span> protons that each has in its atomic nucleus. Hope this helped :)</span>
Answer:
In the Bohr model, electrons can exist only in certain energy levels surrounding the atom.
When electrons jump from a higher energy level to a lower one, they emit light at a wavelength that corresponds to the energy difference between the levels.
The energy levels in each atom are unique.
Explanation:
Be sure to put in your own words.
Edge 2020
~theLocoCoco
Answer:
4.65 L of NH₃ is required for the reaction
Explanation:
2NH₃(g) + H₂SO₄(aq) → (NH₄)₂SO₄(s)
We determine the ammonium sulfate's moles that have been formed.
8.98 g . 1mol / 132.06 g = 0.068 moles
Now, we propose this rule of three:
1 mol of ammonium sulfate can be produced by 2 moles of ammonia
Therefore, 0.068 moles of salt were produced by (0.068 . 29) / 1 = 0.136 moles of NH₃. We apply the Ideal Gases Law, to determine the volume.
Firstly we do unit's conversions:
27.6°C +273 = 300.6 K
547.9 mmHg . 1 atm / 760 mmHg = 0.721 atm
V = ( n . R . T ) / P → (0.136 mol . 0.082 L.atm/mol.K . 300.6K) / 0.721 atm
V = 4.65 L
This will be a double replacement reaction.
First let's figure out what the products would be before we balance it.
AlF₃ + CaO --> Al₂O₃ + CaF₂
Al has a charge of 3+
O has a charge of 2-
so when finding what the product would be, you give one element the subscript of the other charge, and that is how we come up with Al₂O₃. This is what you do for ionic compounds. Remember, an ionic compound is made up of a metal and a nonmetal.
You find CaF₂ similarly. Ca has a charge of 2+ and F has a charge of 1-.
Now let's balance our reaction.
AlF₃ + CaO --> Al₂O₃ + CaF₂
There is one calcium on the left side, and one calcium on the right side
There is one aluminum on the left side but 2 aluminum on the right side
There are 3 fluorine on the left side and 2 on the left side
There is one oxygen on the left side and 3 on the right side
This is obviously not balanced.
We can start off by adding a coefficient of 2 in front of AlF₃ so that way the aluminum will be balanced.
We will now have
2AlF₃ + CaO --> Al₂O₃ + CaF₂
The aluminum atoms are balanced, and this has now increased the fluorine atoms on the left side to 6 and we have 2 fluorine atoms on the right. We can add a coefficient of 3 on CaF₂ so that way fluorine will be balanced.
2AlF₃ + CaO --> Al₂O₃ + 3CaF₂
We now have 1 calcium atom on the left, and 3 calcium atoms on the right. If we add a coefficient of 3 to CaO, we will balance the calcium.
2AlF₃ + 3CaO --> Al₂O₃ + 3CaF₂
You will see now that all the atoms are balanced. Remember when balancing an equation, you can only change the coeffiecients, you may not change the subscripts.
Answer:
B.
Explanation:
- Make a list of the elements with amount in each
- Multiply them out to get them equivalent
- Hope that helped! Please let me know if you need further explanation.